Reasoning · Grade 2-1 Calculating to Meet Conditions

Problem

Place digit cards to maximize or minimize a result

Use the cards 2, 3, 5, 6 each once to build two two-digit numbers. Make an addition and a subtraction, and the difference must not go below zero. Find the largest and smallest sum, and the largest and smallest difference.
Your answer
How to solve
Strategy Look for a Pattern — Place value tells us the tens digits matter ten times as much as the ones digits, so there is a simple rule (pattern) for where the big and small cards should go. I confirm the rule by listing/checking a few arrangements.
1STEP 1

Largest sum: big cards in the tens place

Tens weigh ten times as much, so big cards on top: 63 + 52 = 115.

63 + 52 = 115
2STEP 2

Smallest sum: small cards in the tens place

Flip it — small cards in the tens — and 25 + 36 = 61.

25 + 36 = 61
3STEP 3

Largest difference: biggest number minus smallest number

Biggest minus smallest gives 65 − 23 = 42.

65 - 23 = 42
4STEP 4

Smallest difference: make the two numbers close together

Squeezing the numbers together, 35 − 26 = 9 is the smallest.

35 - 26 = 9
Answer
largest sum 63 + 52 = 115, smallest 25 + 36 = 61, largest difference 65 − 23 = 42, smallest 35 − 26 = 9
All results are within 100-and-a-bit, sensible for two-digit-by-two-digit work. 115 is the most a two-digit sum from these cards can reach and 61 the least; 42 is the widest gap and 9 the narrowest positive gap — each pair (largest vs smallest) brackets the others, so the answers are at the extremes as required.
Takeaway

Put your biggest cards in the tens place to grow a sum, the smallest cards in the tens place to shrink it — that's just Grade 2 place value at work!

  • Largest sum: big cards in the tens place
  • Smallest sum: small cards in the tens place
  • Largest difference: biggest number minus smallest number
  • Smallest difference: make the two numbers close together