Reasoning · Grade 2-2 Making Four-Digit Numbers

Problem

Make numbers from digit cards

Use the cards 1, 3, 7, 0 each once to build four-digit numbers. 0 cannot take the thousands place. Every number you can build is listed in order from least to greatest. Find the greatest, the least, the 6th-greatest and the 6th-smallest.
Your answer
How to solve
Strategy Make a Systematic List — There are only a few four-digit numbers possible, so I can list them in an organized way (grouping by the thousands digit) and put them in order. From the ordered list I can read off the greatest, least, and the 6th values from each end.
1STEP 1

Count how many numbers are possible

Only 1, 3, 7 can lead, so there are 3 × 6 = 18 numbers.

3 × 3 × 2 × 1 = 18
2STEP 2

List each group in order

Grouped by leading digit, the whole list comes out ordered.

1037 < 1073 < … < 7301 < 7310
3STEP 3

Read off least and greatest

The two ends of the list are 1037 and 7310.

least = 1037, greatest = 7310
4STEP 4

Count 6 in from each end

Counting six in from each end gives 7013 and 1730.

6th greatest = 7013, 6th smallest = 1730
Answer
greatest 7310, least 1037, 6th-greatest 7013, 6th-smallest 1730
All numbers use 1, 3, 7, 0 once with no leading zero, the greatest (7310) really is bigger than the least (1037), and there are 18 numbers in total, so a 6th-from-each-end makes sense. The six largest all start with 7 and the six smallest all start with 1, which matches the staircase layout.
Takeaway

List the numbers neatly by their first digit and the order falls right out - then just count six in from each end!

  • Count how many numbers are possible
  • List each group in order
  • Read off least and greatest
  • Count 6 in from each end