Reasoning · Grade 3-1 Setting Up the Equation

Problem

Largest and smallest from flipped cards

Four positive whole numbers satisfy four conditions at once: the greatest plus the least is 487; the least plus the second-least is 70; the greatest plus the second-greatest is 594; the three that are not the greatest add to 206. Find all four and list them from smallest.
Your answer
How to solve
Strategy Work Backwards — Each clue links the totals, so I peel them apart one at a time: combine the clue about all-but-greatest with the least-pair clue to free one number, then chain through the remaining clues to recover the rest.
1STEP 1

Name the four numbers in order

Name them w, x, y, z from smallest and write the four conditions.

z+w=487, w+x=70, z+y=594, w+x+y=206
2STEP 2

Find the second-greatest number y

Taking 70 from 206 gives y = 136.

y = (w+x+y) - (w+x) = 206 - 70 = 136
3STEP 3

Find the greatest number z

594 less 136 gives z = 458.

z = 594 - 136 = 458
4STEP 4

Find the least number w

487 less 458 gives w = 29.

w = 487 - 458 = 29
5STEP 5

Find the second-least number x and order them

70 less 29 gives x = 41: 29, 41, 136, 458.

x = 70 - 29 = 41 → 29 < 41 < 136 < 458
Answer
29, 41, 136, 458
Re-test every clue: 458 + 29 = 487 (clue 1), 29 + 41 = 70 (clue 2), 458 + 136 = 594 (clue 3), and 29 + 41 + 136 = 206 (clue 4). All four hold, and 29 < 41 < 136 < 458 keeps the ordering consistent, so the answer checks out.
Takeaway

Pull the clues apart one subtraction at a time and each hidden number falls right out - just Grade 3 adding and subtracting!

  • Name the four numbers in order
  • Find the second-greatest number y
  • Find the greatest number z
  • Find the least number w
  • Find the second-least number x and order them