Reasoning · Grade 6-2 Loci and Traced Paths

Problem

Path length traced by a rolling circle's center

A circle of radius 1 cm rolls right round the outside of a track. In (1) the track is a circle of radius 3 cm. In (2) it is a square of side 5 cm. Find the length of the path traced by the centre.
(1) 3 cm 1 cm (2) 1 cm 5 cm
Your answer
How to solve
Strategy Draw a Diagram — Draw the track, then draw the dot the centre makes in several rolling positions and join the dots -- the centre's path appears on the page and can be measured. Part (1) is the easier related problem: the path turns out to be one plain circle, and the single idea it teaches (the centre stays 1 cm out from the track) is exactly what part (2) needs. Part (2) then splits into subproblems, one for each straight side and one for each corner, and every piece is either a segment whose length I can read off or an arc whose radius and angle I can name.
1STEP 1

The one idea: the centre stays 1 cm out from the track

The centre stays 1 cm out from the track.

2STEP 2

Part (1): the centre's path is a circle of radius 4 cm

In (1) the centre traces a circle of radius 4 cm.

3 cm + 1 cm = 4 cm
3STEP 3

Part (1): measure that circle

That circle measures 25.12 cm.

4 × 2 × 3.14 = 25.12 (cm)
4STEP 4

Part (2): the straight pieces add up to the square's perimeter

In (2) the straight pieces total 20 cm.

5 × 4 = 20 (cm)
5STEP 5

Part (2): what happens at a corner

At a corner the centre traces an arc.

6STEP 6

Part (2): each corner arc turns 90 degrees

Each arc turns 90 degrees.

180° - 90° = 90°
7STEP 7

Part (2): the four corner arcs make one whole circle

The four arcs make one whole circle.

90° × 4 = 360°, 1 × 2 × 3.14 = 6.28 (cm)
8STEP 8

Part (2): add the straight and the curved

Adding gives (2) as 26.28 cm.

20 + 6.28 = 26.28 (cm)
Answer
25.12, 26.28 cm
20 + 6.28 = 26.28
Both answers are lengths and both came out in centimetres, which is right. In (1) the path must be longer than the 3 cm circle it wraps (3 x 2 x 3.14 = 18.84 cm) and shorter than, say, a 5 cm circle (31.4 cm); 25.12 cm sits between them. It is also exactly 2 x 3.14 = 6.28 cm longer than the 18.84 cm track, which makes sense because the path is one radius further out all the way round. In (2) the path must be longer than the square's own perimeter of 20 cm, since the centre travels outside it, and again the extra is exactly 6.28 cm -- the same 6.28 cm as in part (1). That repeat is the real check: rolling once around any convex track adds one circle of radius 1 cm to the trip, whether the corners are sharp or the track is smooth.
Takeaway

Roll a circle once all the way around any track and its centre travels the length of the track plus exactly one extra circle of the roller's own size.

  • The one idea: the centre stays 1 cm out from the track
  • Part (1): the centre's path is a circle of radius 4 cm
  • Part (1): measure that circle
  • Part (2): the straight pieces add up to the square's perimeter
  • Part (2): what happens at a corner
  • Part (2): each corner arc turns 90 degrees
  • Part (2): the four corner arcs make one whole circle
  • Part (2): add the straight and the curved