Reasoning · Grade 6-1 Fraction and Decimal Calculations

Problem

Simplify messy fraction-decimal expressions

Six expressions mix fractions and decimals: 6.45÷2.55; (4.69×2.32+53.1×0.232)÷2.32; 3/4×2.84÷3 3/5÷(1 1/2×1.42)×1 4/5; (9999×1/6+3333×1/2-6666×1/9)÷7/9-3300; 1993÷1993 1993/1995; 99999.9÷5+9999.9÷5+…+9.9÷5. Each hides a repeated factor. Find the value of each.
Your answer
How to solve
Strategy Organize Information in More Ways — Every one of these six is a trap for anyone who starts calculating immediately: the numbers are ugly on purpose. So before touching a pencil the move is to re-sort each expression until its structure shows — change a decimal into a fraction, move a decimal point from one factor to another so a repeated number appears, pull a common factor out of a sum, or split a number into a round number minus a small piece. That re-organising is tool 15, and what tells me which rewrite to try is tool 5, spotting a number that has already appeared somewhere else in the same line (2.32 in (2), 1.42 in (3), 3333 in (4), 1993 in (5), a whole row of nines in (6)). Once the structure is out in the open, each expression falls into two or three small independent pieces that can be handled one at a time, which is tool 7.
1STEP 1

Decide to reshape first and calculate second

Reshape before calculating.

2STEP 2

(1) Turn both decimals into hundredths

Seen as hundredths, (1) is 2 9/17.

6.45 ÷ 2.55 = 645/100 ÷ 255/100 = 645/100 × 100/255 = 645/255 = 43/17 = 2 9/17
3STEP 3

(2) Make the repeated factor visible, then pull it out

Factoring the repeat, (2) is 10.

(4.69 × 2.32 + 53.1 × 0.232) ÷ 2.32 = (4.69 × 2.32 + 5.31 × 2.32) ÷ 2.32 = 2.32 × (4.69 + 5.31) ÷ 2.32 = 4.69 + 5.31 = 10
4STEP 4

(3) Re-pair each multiplier with a matching divider

Re-pairing, (3) is 1/2.

(3/4 ÷ 3/2) × (2.84 ÷ 1.42) × (9/5 ÷ 18/5) = 1/2 × 2 × 1/2 = 1/2
5STEP 5

(4) Factor out 3333, then let the sevenths cancel

Factoring out 3333, (4) is 33.

3333 × (3/6 + 1/2 - 2/9) ÷ 7/9 - 3300 = 3333 × 7/9 ÷ 7/9 - 3300 = 3333 - 3300 = 33
6STEP 6

(5) Split the mixed number so the 1993s cancel

Splitting the mixed number, (5) is 1995/1996.

1993 ÷ (1993 × 1996/1995) = 1/1996/1995 = 1995/1996
7STEP 7

(6) Add first, using a round number minus a little

Adding first, (6) is 22221.9.

(99999.9 + 9999.9 + 999.9 + 99.9 + 9.9) ÷ 5 = (111110 - 0.5) ÷ 5 = 22222 - 0.1 = 22221.9
Answer
2 9/17, 10, 1/2, 33, 1995/1996, 22221.9
3333 − 3300 = 33
Every answer passes a rough size check. (1) 6.45 is a bit more than twice 2.55 (which is 5.10), so a quotient of 2 9/17 ≈ 2.53 is right. (2) 53.1 × 0.232 is about 12.3 and 4.69 × 2.32 is about 10.9; their sum 23.2 divided by 2.32 is 10 exactly. (3) the chain multiplies by numbers close to 1 and divides by a 3.6, so a small answer like 1/2 is expected, and 1/2 is between 0 and 1 as the mixture of doubling and halving suggests. (4) the bracket is about 1667 + 1667 - 741 ≈ 2593, and 2593 ÷ 7/9 ≈ 3333, so subtracting 3300 leaves a small two-digit number. (5) dividing 1993 by something a hair bigger than 1993 must give an answer just under 1, and 1995/1996 is just under 1. (6) the five numerators total a little under 111110, and a fifth of that is a little under 22222.
Takeaway

When the same number shows up twice in one line, rewrite the expression so it can cancel — the ugly arithmetic was never meant to be done.

  • Decide to reshape first and calculate second
  • (1) Turn both decimals into hundredths
  • (2) Make the repeated factor visible, then pull it out
  • (3) Re-pair each multiplier with a matching divider
  • (4) Factor out 3333, then let the sevenths cancel
  • (5) Split the mixed number so the 1993s cancel
  • (6) Add first, using a round number minus a little