Reasoning · Grade 6-2 Area of the Shaded Region

Problem

Area of a path of constant width

Two curved paths of constant width are shaded, each cut from a circular ring. (1) central angle 45°, inner radius 10 m, width 10 m; (2) central angle 120°, inner radius 6 m, width 6 m. Subtract the inner sector from the outer one; use 3.14 for π. Find each shaded area.
(1) 45° 10 m 10 m (2) 120° 6 m 6 m
Your answer
How to solve
Strategy Identify Subproblems — A curved band is an awkward shape to attack head on, but it is the difference of two shapes that are easy: a big sector minus a small sector cut out of its middle. So each figure becomes two small subproblems plus one subtraction. Inside each subproblem I ask the easier question first - what is the area of the WHOLE circle of that radius? - and then take the (angle/360) share of it. After doing both figures the same way, I look for the pattern hiding in the two answers and find the (midline length) x (width) shortcut the book is steering toward.
1STEP 1

Turn each band into a difference of two sectors

A band is a difference of two sectors.

(shaded band) = (outer sector) - (inner sector)
2STEP 2

Figure (1): read off both radii

In (1) the radii are 10 m and 20 m.

r_inner = 10 m, r_outer = 10 + 10 = 20 m
3STEP 3

Figure (1): what fraction of a circle is 45 degrees?

45 degrees is an eighth of a circle.

45°/360° = 1/8
4STEP 4

Figure (1): subtract the two sector areas

Subtracting, (1) is 117.75 m².

20 × 20 × 3.14 × 45°/360° - 10 × 10 × 3.14 × 45°/360° = 157 - 39.25 = 117.75 m²
5STEP 5

Figure (2): read off both radii and the fraction

In (2) the radii are 6 m and 12 m.

r_inner = 6 m, r_outer = 12 m, 120°/360° = 1/3
6STEP 6

Figure (2): subtract the two sector areas

Subtracting, (2) is 113.04 m².

12 × 12 × 3.14 × 120°/360° - 6 × 6 × 3.14 × 120°/360° = 150.72 - 37.68 = 113.04 m²
7STEP 7

Look at the pattern: midline length times width

Midline times width gives the same.

((10+5) × 2 × 3.14 × 45°/360°) × 10 = 11.775 × 10 = 117.75 m²
Answer
117.75, 113.04
157 − 39.25 = 117.75
Both answers are areas in square metres, which is right, since in each calculation two lengths were multiplied together. The sizes are sensible too. In figure (1) the band lies between the 39.25 square metre inner sector and the 157 square metre outer sector, and 117.75 is between them and equals 157 - 39.25 exactly. A rough sanity estimate helps as well: the band in (1) is 10 m wide and its middle arc is about 11.8 m long, so about 118 square metres, matching. In figure (2) the band is 6 m wide with a middle arc of about 18.8 m, giving about 113 square metres, again matching. Both bands also come out to three quarters of their outer sector (117.75 / 157 = 0.75 and 113.04 / 150.72 = 0.75), which is exactly right whenever the outer radius is double the inner one, because the inner sector is then one quarter of the outer.
Takeaway

A curved path is just a big wedge with a smaller wedge taken out of the middle - and its area is always the middle arc times the width.

  • Turn each band into a difference of two sectors
  • Figure (1): read off both radii
  • Figure (1): what fraction of a circle is 45 degrees?
  • Figure (1): subtract the two sector areas
  • Figure (2): read off both radii and the fraction
  • Figure (2): subtract the two sector areas
  • Look at the pattern: midline length times width