Reasoning · Grade 5-1 Area of Figures

Problem

Area of a complicated composite figure

Figure (1) is an H shape 10 cm tall, notched 4 cm deep and 4 cm wide at the middle of the top and of the bottom, with side bars 2 cm wide each. Figure (2) is a rectangle 12 cm by 9 cm with an L-shaped hole removed. The L is an arm 3 cm wide and 7 cm tall with a foot 3 cm wide and 2 cm tall. Find the area of each figure.
(1) 10 cm 4 cm 4 cm 4 cm 2 cm 2 cm (2) 12 cm 9 cm 7 cm 3 cm 3 cm 2 cm
Your answer
How to solve
Strategy Change Focus / Count the Complement — Both figures are awkward to add up piece by piece but easy to describe as something simple with something simple missing. So instead of chasing the shaded region directly, I draw the smallest rectangle that wraps right around each figure, work out its area, then work out the area of the white part that was taken away and subtract. That turns each question into two or three ordinary rectangle areas — the subproblems — and each of those is just length times width. The only real work left is reading lengths that the drawing does not label, which the diagram supplies once I notice that a full side must equal the pieces it is cut into. Afterwards I add figure (1) up the other way, bar by bar, as an independent check.
1STEP 1

Figure (1): recover the missing width

The unprinted width in (1) is 8 cm.

2 + 4 + 2 = 8 cm
2STEP 2

Figure (1): wrap it in the smallest rectangle

The wrapping rectangle is 80 cm².

8 × 10 = 80 cm²
3STEP 3

Figure (1): subtract the two notches

Removing the two notches gives 48 cm².

4 × 4 = 16, 16 × 2 = 32, 80 - 32 = 48 cm²
4STEP 4

Figure (1): check by cutting it into three bars instead

Cutting it into three bars also gives 48 cm².

2 × 10 × 2 = 40, 10 - 4 - 4 = 2, 4 × 2 = 8, 40 + 8 = 48 cm²
5STEP 5

Figure (2): find the area of the whole rectangle

The whole rectangle in (2) is 108 cm².

12 × 9 = 108 cm²
6STEP 6

Figure (2): find the area of the L-shaped hole

The L-shaped hole is 27 cm².

3 × 7 = 21, 3 × 2 = 6, 21 + 6 = 27 cm²
7STEP 7

Figure (2): subtract, and check the L a second way

Subtracting gives 81 cm².

108 - 27 = 81 cm²; 6 × 2 = 12, 3 × 5 = 15, 12 + 15 = 27
Answer
48, 81 cm²
80 − 32 = 48, 108 − 27 = 81
Both answers are areas, so square centimetres are the right units. For figure (1), 48 square centimetres is less than the 80 of the 8 cm by 10 cm boxing rectangle and more than half of it, which looks right for a shape with two square bites of 16 taken out; and the two independent routes, 80 minus 32 and 40 plus 8, agree exactly. For figure (2), 81 square centimetres is less than the 108 of the full rectangle by exactly the 27 of the hole, and 27 is a modest fraction of 108, matching a drawing in which the white L is clearly the smaller part; splitting the L two different ways gave 27 both times. Adding the answers back also works: 48 + 32 = 80 and 81 + 27 = 108, the two boxing rectangles.
Takeaway

A bumpy shape is just a plain rectangle with a few rectangles missing — find the big one, take the holes away, and the hard shape disappears!

  • Figure (1): recover the missing width
  • Figure (1): wrap it in the smallest rectangle
  • Figure (1): subtract the two notches
  • Figure (1): check by cutting it into three bars instead
  • Figure (2): find the area of the whole rectangle
  • Figure (2): find the area of the L-shaped hole
  • Figure (2): subtract, and check the L a second way