Reasoning · Grade 6-1 Surface Area and Volume of Solids

Problem

Surface area of a composite solid

Two solids are drawn. Solid (1) is a cube with a small cube stuck on. Solid (2) is a block with a smaller block cut away. Find the surface area of each.
(1) 3 cm 3 cm 3 cm 1 cm 1 cm 1 cm (2) 8 cm 9 cm 4 cm 2 cm 3 cm 2 cm
Your answer
How to solve
Strategy Organize Information in More Ways — Adding up nine separate rectangles for solid (2) invites a mistake, and worse, the depth needed for those rectangles is not even printed on the figure. So instead of counting faces where they are, I move them: slide each inward-facing wall of the notch straight out until it fills the hole it left in the outside of the block. Every wall lands on a hole of exactly its own size, so the total area does not change at all - and what is left is a plain rectangular box whose surface area is one short formula. Solid (1) yields to the same idea in reverse, sliding the small cube's front face back into the front face of the big cube. Before any of that, the figure has to be read carefully (tools 17 and 1), because both answers depend on a reading the drawing only half states.
1STEP 1

Read the two figures before touching any arithmetic

Pin down each solid's lengths first.

depth = 3 + 2 = 5 cm, box = 9 × 5 × 8
2STEP 2

Solid (1): start with the plain cube

The plain cube in (1) is 54 cm².

6 × (3 × 3) = 6 × 9 = 54 cm²
3STEP 3

Solid (1): what sticking the small cube on changes

The small cube hides 1 and adds 5.

54 - 1 + 5 = 58 cm²
4STEP 4

Solid (1) again, by sliding a face - the method the rest of the problem needs

So (1) is 58 cm².

9 + (9 × 5) + (1 × 4) = 9 + 45 + 4 = 58 cm²
5STEP 5

Solid (2): write down the notch

Write down the notch in (2).

removed block = 4 × 3 × 6, 8 - 2 = 6
6STEP 6

Solid (2): slide the three inner walls out and watch nothing change

Sliding the three inner walls out leaves it unchanged.

4 × 3 = 12, 4 × 6 = 24, 3 × 6 = 18
7STEP 7

Solid (2): the surface area of that box

That leaves the whole block's 314 cm².

2(9 × 5) + 2(9 × 8) + 2(5 × 8) = 90 + 144 + 80 = 314 cm²
8STEP 8

A note on the other reading of solid (1)

Sliding faces in (1) also gives 58 cm².

54 - 1 + 5 = 58 cm² either way
Answer
58, 314 cm²
54 − 1 + 5 = 58
Check solid (2) the long way, face by face, without any sliding. Top: 9 x 5 = 45 minus the notch footprint 4 x 3 = 12, leaving 33. Notch floor: 12. Bottom: 45. Front: 9 x 8 = 72 minus the notch opening 4 x 6 = 24, leaving 48. Notch back wall: 24. Back: 72. Left: 5 x 8 = 40 minus the notch opening 3 x 6 = 18, leaving 22. Notch right wall: 18. Right: 40. The nine pieces total 33 + 12 + 45 + 48 + 24 + 72 + 22 + 18 + 40 = 314 square centimetres, matching. Solid (1) is sensible too: the plain cube is 54 and adding a small cube can only push the total up a little, and 58 - 54 = 4 is exactly the four side faces of a 1 cm cube. Both answers are in square centimetres, correct for area, and both are far larger than any single face (9 and 72 respectively) yet far smaller than any wild over-count, so the magnitudes sit where they should. Note also that the notch changes the volume of solid (2) a great deal - it removes 4 x 3 x 6 = 72 cubic centimetres out of 360 - while leaving the surface area untouched, which is exactly the point the problem is making.
Takeaway

Push the pushed-in faces back out: a bite taken from a corner leaves the surface area exactly what the whole box had.

  • Read the two figures before touching any arithmetic
  • Solid (1): start with the plain cube
  • Solid (1): what sticking the small cube on changes
  • Solid (1) again, by sliding a face - the method the rest of the problem needs
  • Solid (2): write down the notch
  • Solid (2): slide the three inner walls out and watch nothing change
  • Solid (2): the surface area of that box
  • A note on the other reading of solid (1)