Reasoning · Grade 6-2 Shortest Distance and Surface Area

Problem

Surface area of a drilled cylinder

A narrower cylinder is bored right through a cylinder along its axis. What is left looks like a thick pipe. Each end is a ring and the hole has a wall of its own. Find the surface area.
8 cm 1 cm 2 cm
Your answer
How to solve
Strategy Identify Subproblems — There is no single formula for a drilled cylinder, but there is a formula for every piece of it. So I walk a finger over the whole outside of the solid and split it into parts that never overlap and leave nothing out: the two flat rings at the ends, the curved wall on the outside, and the curved wall inside the tunnel. Each piece is then a one-line calculation — a ring is a big circle take away a small circle, and a curved wall unrolls flat into a rectangle — and the answer is the sum. Before any of that I have to read the figure correctly, because the two marks on the end face are stacked along one line out from the centre and it is easy to mistake the second one for the radius of the whole face.
1STEP 1

Read the two radii off the end face

The two radii are 1 cm and 3 cm.

r = 1 cm, R = 1 + 2 = 3 cm
2STEP 2

Split the surface into four pieces

The surface is two rings, an outer wall and an inner wall.

surface = 2 × (ring) + (outer wall) + (wall of the hole)
3STEP 3

Area of the two end rings

The two rings total 48 cm².

(3 × 3 × 3) - (1 × 1 × 3) = 27 - 3 = 24, 24 × 2 = 48 cm²
4STEP 4

The outside wall unrolls into a rectangle

The outer wall unrolls to 144 cm².

(6 × 3) × 8 = 18 × 8 = 144 cm²
5STEP 5

The wall of the hole unrolls too

The hole's wall is 48 cm².

(2 × 3) × 8 = 6 × 8 = 48 cm²
6STEP 6

Add the four pieces

Adding them gives 240 cm².

48 + 144 + 48 = 240 cm²
7STEP 7

Check it by starting from the whole cylinder instead

Starting from the whole cylinder also gives 240 cm².

198 - 6 + 48 = 240 cm²
Answer
240 cm²
48 + 144 + 48 = 240
The units are right: every piece was a length times a length, so the total is in square centimetres, and the question asks for square centimetres. The size is right too. The outside wall alone is 144, and the two end rings and the tunnel wall are each 48, so 240 is only a little over one and a half times the outside wall — sensible for a shape that is mostly outside wall. It also sits just above the 198 of the un-drilled cylinder, which is what has to happen: drilling loses two small discs worth 6 but gains a tunnel wall worth 48. A quick sanity test on the misreading this problem invites: if the end face had radius 2 cm instead of 3 cm the answer would come out as 2 x (12 - 3) + 12 x 8 + 6 x 8 = 18 + 96 + 48 = 162, not 240, so the picture and the answer agree that the radius is 1 + 2 = 3 cm.
Takeaway

Drilling a hole right through takes away two little discs but adds a whole tunnel wall, so name every surface you could paint before you add anything up.

  • Read the two radii off the end face
  • Split the surface into four pieces
  • Area of the two end rings
  • The outside wall unrolls into a rectangle
  • The wall of the hole unrolls too
  • Add the four pieces
  • Check it by starting from the whole cylinder instead