Reasoning · Grade 6-2 Area of the Shaded Region

Problem

Area of the shaded part (2)

A semicircle of paper with a 12 cm diameter has its curved edge inked. It is slid 3 cm straight down without turning. The shaded band lies between the starting arc and the finishing arc. Find the area of the shaded band.
3 cm 12 cm
Your answer
How to solve
Strategy Draw a Diagram — The crescent itself is a horrible shape - it has two curved sides that are not concentric and it tapers to points. So I refuse to measure it directly. Instead I change focus and look at a bigger, friendlier region that contains it: everything under the starting arc, all the way down to the final diameter. That region is easy, because it is just a semicircle sitting on top of a rectangle. Take the final semicircle out of it and the crescent is what is left. The two semicircles are congruent copies of the same piece of paper, so they cancel and only the rectangle survives.
1STEP 1

Slide a real semicircle and see what the ink sweeps

Slide it and watch where the ink sweeps.

2STEP 2

Change focus: look at the whole region under the starting arc

The band is the region under the starting arc minus the moved semicircle.

(shaded) = (region under the starting arc) - (final semicircle)
3STEP 3

Break the big region into a semicircle and a rectangle

That region splits into a semicircle and a rectangle.

(region under the starting arc) = (starting semicircle) + (12 × 3 rectangle)
4STEP 4

Put the two facts together and watch the semicircles cancel

The semicircles cancel, leaving just the rectangle.

(shaded) = (semicircle) + (rectangle) - (semicircle) = (rectangle)
5STEP 5

Compute the rectangle

That rectangle is 36 cm².

12 × 3 = 36 cm²
6STEP 6

Do it the long way as a check

The long way also gives 36 cm².

(6 × 6 × 3.1 ÷ 2 + 12 × 3) - 6 × 6 × 3.1 ÷ 2 = 55.8 + 36 - 55.8 = 36 cm²
Answer
36 cm²
12 × 3 = 36
The answer is an area in square centimetres, which is right, since two lengths were multiplied. Its size is believable: the band is at most 3 cm thick and spans 12 cm, so it must be under 12 x 3 = 36 square centimetres if you only counted the part between the two straight diameters - and 36 is exactly what the swept strip works out to once the arc that bulges above the top diameter is accounted for. Compare it with the paper itself: the semicircle has area 55.8 square centimetres, so a 36 square centimetre band is a bit under two thirds of the piece of paper, which matches a slide of 3 cm on a shape 6 cm tall. A second sanity check is that the answer depends only on 12 and 3, not on pi - and it should, because a straight slide of ANY shape sweeps an area equal to (width across the direction of travel) x (distance travelled) whenever the shape's outline is the same at top and bottom of the sweep.
Takeaway

Sliding a shape never makes or loses area, so the two semicircles cancel and the inked band is just the 12 cm by 3 cm rectangle it swept.

  • Slide a real semicircle and see what the ink sweeps
  • Change focus: look at the whole region under the starting arc
  • Break the big region into a semicircle and a rectangle
  • Put the two facts together and watch the semicircles cancel
  • Compute the rectangle
  • Do it the long way as a check