Reasoning · Grade 5-2 Exploring the Cube

Problem

Angles between segments drawn on a cube

A cube has its top and bottom corners labelled. Nothing is drawn on the cube itself. The segments have to be imagined. Find the size of each of the three named angles.
A B C D E F G H A B C D E F G H A B C D E F G H
Your answer
How to solve
Strategy Draw a Diagram — Each question names three vertices, and three points always make a triangle, so the plan is the same three times: draw the triangle onto the cube, work out what kind of triangle it is, and read the angle off. To classify the triangle I only need to sort its three sides into edges, face diagonals and cube diagonals, because all the edges are equal to one another and all the face diagonals are equal to one another. That turns a three-dimensional question into an ordinary flat-triangle question, which is the whole point of splitting it into subproblems. Building or holding a cube and stretching a piece of string between the named corners makes each triangle real, and it keeps the distorted picture from misleading me.
1STEP 1

Sort out the three possible lengths first

A cube has only edge, face diagonal and body diagonal.

edge < face diagonal < cube diagonal
2STEP 2

(1) Locate triangle FHG — it lies flat in the bottom face

The first triangle lies flat in the bottom face.

GF = GH = edge, ∠ FGH = 90°
3STEP 3

(1) Finish: the base angles of a right isosceles triangle are 45°

Right isosceles, so the base angle is 45 degrees.

∠ GFH = ∠ FHG = (180° - 90°)/2 = 45°
4STEP 4

(2) Notice that GH sticks straight out of the face that contains BG

In the second an edge sticks straight out of a face.

GH ⊥ face BCGF, GB ⊂ face BCGF
5STEP 5

(2) Read off the right angle

So that angle is 90 degrees.

∠ BGH = 90°
6STEP 6

(3) Check the three sides of triangle AFH

In the third all three sides are face diagonals.

AF, FH, AH are diagonals of faces ABFE, EFGH, ADHE
7STEP 7

(3) Finish: the triangle is equilateral, so every angle is 60°

Equilateral, so the angle is 60 degrees.

AF = FH = AH → ∠ AFH = 180°/3 = 60°
8STEP 8

Check all three with a real cube

A real cube confirms all three.

Answer
45, 90, 60 degrees
180 − 90 = 90, 90 ÷ 2 = 45
All three answers are between 0° and 180°, as any angle of a triangle must be, and none of them depends on the size of the cube, which is right because no length was given. Each also sits sensibly inside its own triangle: triangle FHG is right-angled at G, so 45° + 45° + 90° = 180°; triangle BGH has the cube diagonal BH as its longest side, and the largest angle of a triangle must be opposite the longest side, so the 90° belongs at G and not at B or H; triangle AFH has three equal sides and 60° + 60° + 60° = 180°. The three answers are also the only three sizes this kind of question can produce — 45°, 60° and 90° — because a triangle on the corners of a cube can only be right isosceles, equilateral, or the edge-plus-face-diagonal right triangle of part (2).
Takeaway

On a cube there are only three lengths - edge, face diagonal, cube diagonal - so just naming the sides of your triangle tells you whether the angle is 45°, 60° or 90°.

  • Sort out the three possible lengths first
  • (1) Locate triangle FHG — it lies flat in the bottom face
  • (1) Finish: the base angles of a right isosceles triangle are 45°
  • (2) Notice that GH sticks straight out of the face that contains BG
  • (2) Read off the right angle
  • (3) Check the three sides of triangle AFH
  • (3) Finish: the triangle is equilateral, so every angle is 60°
  • Check all three with a real cube