Reasoning · Grade 4-2 Triangles and Angles

Problem

Find the hidden isosceles triangle

A square ABCD is drawn. An equilateral triangle EBC stands inside it on the bottom side BC. A straight line runs from A through E. Find the marked angle.
A D B C E F 1
Your answer
How to solve
Strategy Identify Subproblems — Nothing in the picture touches the marked angle directly, so I cannot get at it in one move. Instead I hunt for a smaller triangle whose angles I can work out completely, and then pass what I learn along to E. The square and the equilateral triangle share the side BC, which means several segments secretly have the same length; marking those equal lengths on the drawing turns triangle ABE into an isosceles triangle that nobody has pointed out. Once that hidden triangle is solved, the straight line through A, E and F carries the answer the rest of the way.
1STEP 1

Mark every segment that has the same length

Matching sides hide an isosceles triangle.

AB = BC = EB → △ ABE is isosceles with AB = EB
2STEP 2

Find the apex angle of the hidden triangle

Its apex angle is 90 − 60 = 30 degrees.

∠ ABE = ∠ ABC - ∠ EBC = 90° - 60° = 30°
3STEP 3

Get the base angles of triangle ABE

Its base angles are 75 degrees each.

∠ BAE = ∠ AEB = (180° - 30°) ÷ 2 = 150° ÷ 2 = 75°
4STEP 4

Add up the three angles that sit along the straight line at E

At E the three angles lie along a straight line.

∠ AEB + ∠ BEC + ∠ FEC = 180°
5STEP 5

Solve for the marked angle

Subtracting gives 45 degrees.

∠ FEC = 180° - 75° - 60° = 45°
Answer
45 degrees
180 − 75 − 60 = 45
The answer is an angle, so degrees are the right unit, and 45° is a sensible size: in the figure ① is clearly acute and clearly smaller than the 60° corner of the equilateral triangle right beside it, which is exactly what 45 < 60 says. The three pieces at E also close up perfectly, 75° + 60° + 45° = 180°, so no part of the straight angle has been lost or counted twice. As one more check, ∠ BAE = 75° makes ∠ EAD = 90° - 75° = 15°, a small angle — and that is why the line from A meets the right side at F only a little below D, exactly as drawn.
Takeaway

When a square and an equilateral triangle share a side, all of those sides are the same length — mark them, and a hidden isosceles triangle appears that hands you the angle you need.

  • Mark every segment that has the same length
  • Find the apex angle of the hidden triangle
  • Get the base angles of triangle ABE
  • Add up the three angles that sit along the straight line at E
  • Solve for the marked angle