Reasoning · Grade 3-2 Finding Sums Using Products

Problem

Sum of consecutive odds and evens

Adding consecutive odd numbers starting at 1 always makes a perfect square. Each new odd wraps one more L-shaped layer around a square of dots. So the first n odds total n × n. Write 1+3+5+7+9+11 as a product and find the sum of the odds up to 33.
Your answer
How to solve
Strategy Look for a Pattern — The three given pictures reveal a rule — the sum of the first n odd numbers is n × n. Drawing the next square confirms it, then I extend the same rule to count how many odd numbers reach 33.
1STEP 1

Read the rule from the squares

Each new odd wraps one L-shaped layer round the square.

1 + 3 + 5 + … = (how many odds) × (how many odds)
2STEP 2

(1) Draw and name the next square

Six odds fill 6 × 6 = 36.

1 + 3 + 5 + 7 + 9 + 11 = 6 × 6 = 36
3STEP 3

(2) Count the odd numbers up to 33

33 is the 17th odd number.

(33 + 1) ÷ 2 = 17
4STEP 4

(2) Apply the square rule

So the sum is 17 × 17 = 289.

1 + 3 + 5 + … + 31 + 33 = 17 × 17 = 289
Answer
6 × 6 = 36, 289
Check the rule on a known case: the first 4 odds give 4×4 = 16, and 1+3+5+7 = 16 — correct. For (2), 17×17 = 289 sits sensibly above the 16-number sum 16×16 = 256, since one more odd number (33) is added. Magnitudes are reasonable.
Takeaway

Adding odd numbers from 1 builds a perfect square — just count how many you added and multiply that by itself. Pure Grade 3 multiplication!

  • Read the rule from the squares
  • (1) Draw and name the next square
  • (2) Count the odd numbers up to 33
  • (2) Apply the square rule