Reasoning · Grade 2-2 Problem Solving with Tables

Problem

Count outcomes with a table

Two dice numbered 1 to 6 are rolled and we take the sum. Order counts, so (1,5) and (5,1) are different, and the sums run from 2 to 12. Fill the 6x6 table, count the ways to make 6, and name the most frequent sum.
Your answer
How to solve
Strategy Make a Systematic List — Filling the 6 by 6 table is a complete, organized list of all 36 outcomes, so no sum is missed. Once the table is full, counting how many cells hold a 6 answers part (2), and spotting which sum appears in the most cells answers part (3).
1STEP 1

Fill in the sum table

Adding the two dice per cell fills from 2 down to 12.

cell = (row die) + (column die)
2STEP 2

Count the ways to make 6

The pairs making 6 run (1,5) to (5,1): 5 ways.

1+5, 2+4, 3+3, 4+2, 5+1 → 5 ways
3STEP 3

Find the most common sum

Counting cells, 7 takes six — the whole diagonal — the most of any sum.

#(7) = 6 > #(6) = #(8) = 5 > …
Answer
5 ways to make 6, and 7 is the most frequent sum
There are 6 x 6 = 36 cells in total. Adding up the counts 1+2+3+4+5+6+5+4+3+2+1 gives 36, which matches, so no outcome was missed or double-counted. The counts are symmetric and peak at 7, which makes sense because 7 is the middle sum and can be made the most ways.
Takeaway

Fill the grid neatly and the answers fall out by counting - the middle sum 7 wins because it has the most ways, all with Grade 2 addition!

  • Fill in the sum table
  • Count the ways to make 6
  • Find the most common sum