Problem
Reasoning · Grade 2-1 Making Numbers
List the value of one dart
One dart is 10, 50 or 100, so list pairs with the smaller score first.
Treating the rings like coin values keeps the choices small and concrete — only three options per dart.
2.MD.C.8Make A Systematic ListPair the first dart = 10 with the second dart
With 10 first the totals are 20, 60, 110.
Holding the first dart fixed at the smallest value and sweeping the second is the no-skip way to list pairs.
2.NBT.B.5Make A Systematic ListPair the first dart = 50 with a second dart of 50 or more
With 50 first only two new pairs remain: 100, 150.
Starting the second dart at 50 (not 10) avoids re-listing the 10+50 pair, so nothing is double-counted.
2.NBT.B.5Make A Systematic ListStarting the second dart at the first dart's value, never below it, lists every pair once and no pair twice.
Why?
Grouping by the first dart's value means a pair falls into exactly one group, so the groups can never overlap and none is forgotten.
Why?
Two darts landing on 10 and 50 give the same score whichever was thrown first, so the pair is one thing and deserves one line in the list.
Pair the first dart = 100 with a second dart of 100
With 100 first just one new pair is left: 200.
By now the only fresh pair is the two biggest darts together, which matches the worked example of 200.
2.NBT.B.7Make A Systematic ListCollect every distinct total
Together, with no repeats: 20, 60, 100, 110, 150, 200.
Putting the totals in order confirms each pair gave a different sum, so there are exactly six possible scores.
2.NBT.A.4Guess And CheckList the dart pairs smallest-first so you never repeat one, then add — Grade 2 addition finds all six scores!
- List the value of one dart
- Pair the first dart = 10 with the second dart
- Pair the first dart = 50 with a second dart of 50 or more
- Pair the first dart = 100 with a second dart of 100
- Collect every distinct total