Reasoning · Grade 2-1 Calculating Cleverly

Problem

Simplify long add-subtract chains

Five long chains are to be worked out by pairing or by the middle term, not term by term. Read strictly left to right. Find the value of (1) 5+6+…+15, (2) 2+4+…+28, (3) 1+1+2+2+…+9+9, (4) 50−49+48−47+…+40−39 and (5) 99+98−97+…+90−89.
Your answer
How to solve
Strategy Look for a Pattern — Each chain hides a regular structure: equally spaced terms have a constant pair-sum (tool 5), and the +/- chains collapse when you re-group adjacent terms into small differences (tool 16). Pairing turns a long sum into a few easy multiplications, and grouping the differences shrinks a scary expression to a tiny one.
1STEP 1

(1) Pair from the ends around the middle

(1) Pairing the ends gives five 20s plus the middle 10: 110.

(5+15)+(6+14)+(7+13)+(8+12)+(9+11)+10 = 5 × 20 + 10 = 110
2STEP 2

(2) Pair the even numbers

(2) The 14 evens make seven 30s: 210.

(2+28)+(4+26)+(6+24)+(8+22)+(10+20)+(12+18)+(14+16) = 7 × 30 = 210
3STEP 3

(3) Solve an easier version, then double

(3) Each of 1 to 9 appears twice, so double 45: 90.

2 × (1+2+…+9) = 2 × 45 = 90
4STEP 4

(4) Group each subtraction with the next addition

(4) Bundling neighbours leaves six 1s: 6.

(50-49)+(48-47)+(46-45)+(44-43)+(42-41)+(40-39) = 1 × 6 = 6
5STEP 5

(5) Keep the lead term, then group the rest

(5) Leaving 99 aside, the rest bundles into five 1s: 99 + 5 = 104.

99 + (98-97)+(96-95)+(94-93)+(92-91)+(90-89) = 99 + 5 = 104
Answer
(1) 110 (2) 210 (3) 90 (4) 6 (5) 104
Each result is sensible. (1) 11 numbers averaging about 10 should total near 110. (2) 14 evens averaging 15 should total near 210. (3) just (1+...+9) doubled = 90. (4) twelve terms collapsing to six +1 steps = 6, a small number as expected. (5) about 99 plus a little = 104. Spot-check (1) by the middle-term rule: 11 × 10 = 110, matching the pairing.
Takeaway

Pair the ends or bundle the +/− steps and a scary-long chain becomes a few easy sums — pure Grade 2 number sense!

  • (1) Pair from the ends around the middle
  • (2) Pair the even numbers
  • (3) Solve an easier version, then double
  • (4) Group each subtraction with the next addition
  • (5) Keep the lead term, then group the rest