Problem
From the 'number of snacks bought' graph, bread was bought 16 times.
The bread bar in the count graph reaches 16 items.
3.MD.B.3Identify SubproblemsFrom the 'price of one snack' graph, one bread costs $0.70.
The bread bar in the price graph reaches 70 cents per item.
3.MD.B.3Identify SubproblemsTotal money = number of breads times price of one bread. Units: 16 items times $0.70 per item gives dollars. Compute 16 times 0.70.
Multiplying a count by a price-per-item always gives total cost in dollars.
4.OA.A.3Analyze The UnitsMultiplying bread's count of 16 by the price of one bread, $0.70, gives the total money the class spent on bread.
The total spent on bread is every single bread's cost added together, and since each bread carries the same 0.70.
The money for bread is spread across the 16 breads with none skipped and none charged twice, so those 16 separate costs pile back up into the one total spent.
Every bread has the identical 0.70 sixteen times is sixteen equal groups of 0.70 counts.
Pull bread's number from one graph and bread's price from the other, then multiply count times price - linking two graphs is just Grade 4 cost = number times price!