Reasoning · Grade 6-2 Surface Area of Cube Stacks

Problem

Surface area unchanged by removing a cube

16 cubes on a 3 by 3 floor: 8 on level 1 (a front corner empty), 7 on level 2, 1 on top. Red is the lone top cube, yellow the centre of level 2, blue a back corner, green front-middle on level 1 by the gap, nothing above. Say how the surface area changes as each is removed.
Your answer
How to solve
Strategy Change Focus / Count the Complement — Recomputing the whole surface area of a 16-cube solid four separate times is slow and easy to get wrong. Instead I change focus and look only at what actually changes when one cube leaves: its own faces disappear from the outside, and the faces it was covering appear. That reduces each case to one small count — how many of this cube's 6 faces were touching a neighbouring cube? Building the solid with real blocks (or picturing it level by level) makes that count easy to see, and writing the four cubes in a short table keeps them straight. Once I derive the rule once, the four questions become four countings of neighbours rather than four surface-area computations.
1STEP 1

Derive the rule: the change is 2k - 6, where k is the number of touching faces

With k touching faces the change is 2k minus 6.

change = (faces newly exposed) - (faces lost) = k - (6 - k) = 2k - 6
2STEP 2

Read the rule: only k = 3 leaves the surface area unchanged

So only k equal to 3 leaves it unchanged.

k = 1 → -4, k = 2 → -2, k = 3 → 0, k = 4 → +2, k = 5 → +4
3STEP 3

(1) The red cube: k = 1, so the surface area shrinks by 4 square inches

The red one has k of 1, so it drops by 4.

2 × 1 - 6 = -4
4STEP 4

(2) The blue cube: k = 3, so the surface area does not change

The blue one has k of 3, so it is unchanged.

2 × 3 - 6 = 0
5STEP 5

(3) The yellow cube: k = 4, so the surface area grows by 2 square inches

The yellow one has k of 4, so it grows by 2.

2 × 4 - 6 = +2
6STEP 6

(4) The green cube: k = 2, so the surface area shrinks by 2 square inches

The green one has k of 2, so it drops by 2.

2 × 2 - 6 = -2
7STEP 7

Collect the four cases into one table

The four cases give −4, 0, +2, −2.

red k=1 → -4, blue k=3 → 0, yellow k=4 → +2, green k=2 → -2
Answer
−4, 0, +2, −2 square inches
2 × 3 − 6 = 0
The units are right: each cube face is 1 square inch, so every change is a whole number of square inches, and all four answers are whole numbers. The magnitudes are sensible: the biggest possible change from removing one cube is 6 square inches in either direction (a completely free cube, k = 0, or a completely buried one, k = 6), and none of these four cases is that extreme, so answers between -4 and +2 are in range. The signs match common sense too: red is the most exposed cube in the solid and removing it shrinks the skin the most, while yellow is the most buried of the four and removing it is the only case that adds skin. As a full check, the whole solid has surface area 44 square inches; removing red leaves 40, removing blue leaves 44, removing yellow leaves 46, and removing green leaves 42 - differences of -4, 0, +2 and -2, exactly as claimed.
Takeaway

Count how many neighbours a cube has: 3 neighbours means you can pull it out and the surface area does not change at all.

  • Derive the rule: the change is 2k - 6, where k is the number of touching faces
  • Read the rule: only k = 3 leaves the surface area unchanged
  • (1) The red cube: k = 1, so the surface area shrinks by 4 square inches
  • (2) The blue cube: k = 3, so the surface area does not change
  • (3) The yellow cube: k = 4, so the surface area grows by 2 square inches
  • (4) The green cube: k = 2, so the surface area shrinks by 2 square inches
  • Collect the four cases into one table