Reasoning · Grade 6-1 Prisms and Pyramids

Problem

Count vertices, faces, edges of prisms and pyramids

There are six matchsticks, all the same length. All six are used each time, joined end to end. They never lie across one another. Build arrangements showing exactly 1, 2 and 4 equilateral triangles.
Your answer
How to solve
Strategy Create a Physical Representation — The first two arrangements come straight out of playing with real matchsticks: six sticks either make one big triangle with two sticks to a side, or two little triangles with one stick to a side. The fourth-triangle case resists every flat attempt, so instead of trying arrangements at random I count how many stick-slots four triangles need. That count says each stick has to serve two triangles at once, which is impossible for the stick on the outside edge of a flat figure — and that is exactly the hint that the sticks have to leave the table and close up into a solid.
1STEP 1

Fix what counts as a triangle here

A triangle's side can be one or two sticks.

side 1 stick → 3 × 1 = 3 sticks; side 2 sticks → 3 × 2 = 6 sticks
2STEP 2

Exactly 1 triangle: one big triangle with two sticks to a side

One big triangle with two-stick sides shows 1.

2 + 2 + 2 = 6 sticks, 1 equilateral triangle
3STEP 3

Exactly 2 triangles: two separate small triangles

Two separate small triangles show 2.

3 + 3 = 6 sticks, 2 equilateral triangles
4STEP 4

Count the stick-slots four triangles would need

Four triangles need each stick in two triangles.

4 × 3 = 12 sides needed, 12 ÷ 6 = 2 triangles per stick
5STEP 5

See why that is impossible flat on the table

Flat, the outermost stick makes that impossible.

outermost stick: at most 1 triangle ≠ 2 required
6STEP 6

Leave the table: build a triangular pyramid

Built upwards it becomes a triangular pyramid with 4.

3 sticks (base) + 3 sticks (rising to one apex) = 6 sticks, 4 triangular faces
7STEP 7

Check the solid by counting its vertices, faces and edges

4 vertices, 4 faces and 6 edges check out.

v = 4, f = 4, e = (4 × 3)/2 = 6, v + f - e = 4 + 4 - 6 = 2
Answer
one big triangle, two small triangles, a triangular pyramid
2 + 2 + 2 = 6, 3 + 3 = 6
Each of the three arrangements uses all six sticks and no more: 2 + 2 + 2 = 6, 3 + 3 = 6, and the pyramid's 6 edges. The counts are exact, not 'at least': the big triangle is empty inside so no smaller triangle hides in it, and the two small triangles are separate so they cannot combine into a third. The four-triangle answer is forced rather than found by luck — 4 triangles need 12 sides, 6 sticks can supply 12 only if each stick is shared by 2 triangles, and the only way every stick has a triangle on both sides is for the figure to close up into a solid. The triangular pyramid is that solid, and counting its parts gives exactly 4 faces and 6 edges, matching the sticks available. A machine search over flat arrangements of six unit sticks confirms the flat maximum is 2 triangles, never 4.
Takeaway

Four triangles from six sticks needs every stick to have a triangle on both sides — and only a solid can do that, so build a pyramid instead of a picture.

  • Fix what counts as a triangle here
  • Exactly 1 triangle: one big triangle with two sticks to a side
  • Exactly 2 triangles: two separate small triangles
  • Count the stick-slots four triangles would need
  • See why that is impossible flat on the table
  • Leave the table: build a triangular pyramid
  • Check the solid by counting its vertices, faces and edges