Reasoning · Grade 6-2 Mixed Fraction and Decimal Calculations

Problem

Split fractions to telescope a sum

An example rule: 1/2-1/3 = (3-2)/(2×3), and 1/2+1/3 = (3+2)/(2×3). Read backwards it splits these four: 1/(1×2)+…+1/(5×6); 2/(1×3)+…+2/(9×11); 1+3 1/6+5 1/12+…+15 1/72; 1-5/6+7/12-…+19/90. Find the value of each of the four.
Your answer
How to solve
Strategy Look for a Pattern — The Examples box is a pattern waiting to be read in reverse, so Looking for a Pattern is the whole first move: find what the numerator and the denominator of the answer have to do with the two starting denominators. After that the work is re-writing — every term gets swapped for a different but equal form, which is Organizing the Information in More Ways, and the payoff is that neighbouring pieces then destroy each other. The four expressions are independent, so I treat them as four subproblems and use each one to set up the next: (1) and (2) train the difference form, (3) reuses it inside mixed numbers, and (4) needs the sum form instead.
1STEP 1

Read the rule off the examples, then turn it around

Read the examples' rule backwards.

(b-a)/(a × b) = 1/a - 1/b (b+a)/(a × b) = 1/a + 1/b
2STEP 2

(1) Split each term into a difference, then watch the middles cancel

Split, (1) telescopes to 5/6.

(1-1/2)+(1/2-1/3)+(1/3-1/4)+(1/4-1/5)+(1/5-1/6) = 1 - 1/6 = 5/6
3STEP 3

(2) The numerator 2 matches a gap of 2, so the same difference form works

The top matches the gap, so (2) is 10/11.

2/(1 × 3)+2/(3 × 5)+2/(5 × 7)+2/(7 × 9)+2/(9 × 11) = 1 - 1/11 = 10/11
4STEP 4

(3) Break the mixed numbers into two piles first

Split (3) into whole parts and fractions.

(1+3+5+7+9+11+13+15) + (1/6+1/12+1/20+1/30+1/42+1/56+1/72) = 64 + (…)
5STEP 5

(3) Factor each denominator into consecutive numbers, then telescope

Factoring the bottoms gives 64 7/18.

1/(2 × 3)+1/(3 × 4)+…+1/(8 × 9) = 1/2-1/9 = 7/18, 64 + 7/18 = 64 7/18
6STEP 6

(4) This one needs the SUM form, not the difference form

(4) must be split in the sum form.

5/6=(3+2)/(2 × 3)=1/2+1/3, 7/12=(4+3)/(3 × 4)=1/3+1/4, 19/90=(10+9)/(9 × 10)=1/9+1/10
7STEP 7

(4) Remove the brackets and let the alternating signs do the cancelling

Alternating signs cancel, leaving 3/5.

1-(1/2+1/3)+(1/3+1/4)-(1/4+1/5)+…+(1/9+1/10) = 1-1/2+1/10=3/5
Answer
5/6, 10/11, 64 7/18, 3/5
1 − 1/6 = 5/6
All four answers are the right size. (1) The five terms are 1/2, 1/6, 1/12, 1/20, 1/30, each smaller than the last, and 0.5 + 0.167 + 0.083 + 0.05 + 0.033 = about 0.833, which is 5/6. (2) The terms 2/3, 2/15, 2/35, 2/63, 2/99 add to about 0.667 + 0.133 + 0.057 + 0.032 + 0.020 = about 0.909, which is 10/11. (3) The whole parts alone already give 64 and the seven fractions are all small, so the answer must be a little over 64 but under 65 — and 7/18 is under 1, so 64 7/18 fits. (4) The terms alternate and shrink towards 1/5 in size, so the value should sit between the first two partial sums 1 and 1 - 5/6 = 1/6; 3/5 = 0.6 is indeed between 0.167 and 1. Adding parts (1) and (4) straight through with common denominators 60 and 2520 confirms 5/6 and 3/5 exactly.
Takeaway

Check the numerator against the two factors underneath: if it is their difference the fraction splits into a subtraction, if it is their sum it splits into an addition — and then whole rows of fractions wipe each other out.

  • Read the rule off the examples, then turn it around
  • (1) Split each term into a difference, then watch the middles cancel
  • (2) The numerator 2 matches a gap of 2, so the same difference form works
  • (3) Break the mixed numbers into two piles first
  • (3) Factor each denominator into consecutive numbers, then telescope
  • (4) This one needs the SUM form, not the difference form
  • (4) Remove the brackets and let the alternating signs do the cancelling