Reasoning · Grade 6-2 Optimal Design

Problem

Farthest travel under a carry limit

Two soldiers are 160 km from base. One day's rations carries a soldier 20 km. Nobody may set out with more than 6 days' rations. Find how one of them can reach the base.
160 km Village Base
Your answer
How to solve
Strategy Draw a Diagram — The two limits in this problem are written in different units -- one is a distance, the other a number of days of food -- so the first job is to put them on the same footing by measuring everything in days. Once the journey is 8 days long and the sack holds 6 days, the shortfall is a plain 2 days, and the whole problem becomes 'get 2 extra days of food into the walker's sack without breaking the 6-day cap'. Then a day-by-day picture does the rest: draw a line marked 0 to 8 days, put a row of ration dots under each soldier, and cross one dot off per day. Trying the handover on day 1, then day 2, then day 3 and checking each against the two rules is exactly the kind of short, bounded guess-and-check this problem invites, and listing the outcomes side by side shows that only one of them survives both rules.
1STEP 1

Measure the journey in days instead of kilometres

In days, the trip needs 8 days' rations.

160 ÷ 20 = 8 days
2STEP 2

See exactly how far short one soldier falls

Carrying six, a soldier is 2 days short.

6 × 20 = 120 km, 160 - 120 = 40 km, 8 - 6 = 2 days
3STEP 3

Realise the extra food must be handed over out in the desert

That shortfall must be handed over on the way.

4STEP 4

Try the handover on different days and check both rules

Trying each day, only day 2 works.

day 1{:} 5+1=6 < 7; day 3{:} 3-3=0 to spare; day 2{:} 4+2=6=6
5STEP 5

Write out the plan and follow the food day by day

Then the walker holds 6 days' rations.

2 × 20 = 40 km; 6 - 2 = 4; 4 - 2 = 2 (escort); 4 + 2 = 6 (walker)
6STEP 6

Check that Soldier 2 makes it all the way

Already 40 km along, he reaches the base.

6 × 20 = 120 km, 40 + 120 = 160 km
Answer
walk together 2 days, hand over 2 days' rations, turn back
40 + 120 = 160
Every quantity stays in days of food or kilometres, and the two match up at 20 km per day throughout. All the numbers land where they should: nobody ever holds more than 6 days' rations (Soldier 2 is at exactly 6 at the handover, which the rule allows), nobody ever holds a negative amount, and each soldier's food runs out precisely as he arrives -- Soldier 1 at the village, Soldier 2 at the base. The total food eaten is a good cross-check: Soldier 1 walks 40 km out and 40 km back, which is 80 km or 4 days, and Soldier 2 walks the full 160 km, which is 8 days; that is 12 days of food in all, and 12 is exactly the 6 + 6 the two men carried out of the village, with nothing left over and nothing missing.
Takeaway

Turn the kilometres into days of food, and the escort's job becomes obvious: walk 2 days, hand over 2 days, keep 2 days to get home.

  • Measure the journey in days instead of kilometres
  • See exactly how far short one soldier falls
  • Realise the extra food must be handed over out in the desert
  • Try the handover on different days and check both rules
  • Write out the plan and follow the food day by day
  • Check that Soldier 2 makes it all the way