Reasoning · Grade 6-2 Shortest Distance and Surface Area

Problem

Central angle of a cone net

The net of a cone is drawn. The sector becomes the side and the circle becomes the base. The sector's radius is 9 cm and the base circle's radius is 3 cm. Find the sector's central angle.
1 9 cm 3 cm
Your answer
How to solve
Strategy Create a Physical Representation — Cut the two pieces out and try to build the cone: the only way the sector's curved edge can be taped all round the rim of the base circle is if those two curves have the same length. That single sentence turns an angle question into a length question, and lengths are something you can compute. Then, rather than attack the sector head-on, solve the easier related problem first — how long is the rim of a whole circle of radius 9 cm? — and ask what fraction of it the sector's arc is. That fraction is the same fraction of 360 degrees.
1STEP 1

See what the folding forces

Folded, the arc meets the base's rim.

(arc of the sector) = (circumference of the base circle)
2STEP 2

Measure the base circle's rim

The base's rim is 18.84 cm.

3 × 2 × 3.14 = 18.84 cm
3STEP 3

Solve the easier related problem: a whole circle of radius 9 cm

A full circle of radius 9 is 56.52 cm.

9 × 2 × 3.14 = 56.52 cm
4STEP 4

Find what fraction of the whole circle the sector is

The sector is a third of the whole circle.

18.84/56.52 = 1/3 → (angle)/360° = 1/3
5STEP 5

Take a third of a full turn

A third of a full turn is 120 degrees.

(angle) = 360° × 1/3 = 120°
6STEP 6

Notice that 3.14 was never actually needed

The ratio of radii alone also gives 120 degrees.

(angle) = 360° × (base radius)/(slant height) = 360° × 3/9 = 120°
Answer
120 degrees
360 × 3 ÷ 9 = 120
120 degrees is between 0 and 360, so it can genuinely be a sector's central angle, and it is a third of a full turn — which matches the picture, where the sector is clearly a good deal more than a quarter circle but well short of a half circle. Check the lengths directly: a 120-degree sector of radius 9 cm has an arc of 9 x 2 x 3.14 x 120/360 = 56.52/3 = 18.84 cm, and the base circle's circumference is 3 x 2 x 3.14 = 18.84 cm. They match, so the net really does close up. The shortcut agrees too: 360 x 3/9 = 120. And it passes a sanity test on size — the base radius is a third of the slant height, so the sector must be a third of a circle; if the base were bigger the angle would be bigger, and a base radius equal to the slant height would need the whole 360 degrees, meaning a flat disc rather than a cone.
Takeaway

The curved edge of the flat piece has to wrap exactly round the base circle, so the angle is just 360° times base radius over slant height — and pi cancels right out.

  • See what the folding forces
  • Measure the base circle's rim
  • Solve the easier related problem: a whole circle of radius 9 cm
  • Find what fraction of the whole circle the sector is
  • Take a third of a full turn
  • Notice that 3.14 was never actually needed