Reasoning · Grade 6-1 Regular Polyhedra

Problem

Vertex labels on a regular octahedron net

A regular octahedron has its six vertices named. Beside it is a net of that same solid. One triangle of the net is already labelled. Fill in the names on the rest of the net.
A F B D C E A B C
Your answer
How to solve
Strategy Create a Physical Representation — Guessing which points meet by eye is exactly how this kind of question goes wrong, so instead I fold the net one triangle at a time. The trick is that I never need to picture the whole solid at once. Two triangles that touch along an edge of the net are two faces that touch along that edge of the solid — and on an octahedron every edge has exactly two faces, so once I know one of them, the other is forced. The net's 8 triangles form a chain, so I start from the one triangle whose three names are already printed and walk along the chain, and at every step exactly one new name gets decided. First I list the octahedron's 8 faces so I have something to look each edge up in.
1STEP 1

List the 8 faces of the octahedron

List the solid's eight faces.

upper: ABC, ACD, ADE, AEB lower: FBC, FCD, FDE, FEB
2STEP 2

Start from the triangle that is already named

Start from the labelled triangle.

3STEP 3

Fold once: the first strip triangle, so L1 = F

Each shared edge has only one other face, fixing the name.

edge BC ⊂ {ABC, FBC} → L₁ = F
4STEP 4

Keep walking: L2 = D, then U3 = A

Walking on, fill the lower row.

edge FC → FCD, L₂ = D edge CD → ACD, U₃ = A
5STEP 5

Finish the strip: L3 = E, U4 = B, L4 = F

Finish the strip and fill the upper row.

DA → ADE, L₃ = E AE → AEB, U₄ = B EB → FEB, L₄ = F
6STEP 6

The last triangle: BOT = D

The last triangle's apex is forced too.

edge EF ⊂ {FEB, FDE} → BOT = D
7STEP 7

Check every name collects a full 240 degrees

Each name collects four triangles.

4 × 60° = 240° at every vertex; 8 × 3 = 24 = 6 × 4
8STEP 8

Check that opposite vertices never touch

No triangle holds two opposite vertices.

Answer
F, D, E, F / A, B / D
8 × 3 = 24 = 6 × 4
The ten net points carry six different names, which is right because the octahedron has six vertices, and the counts fit: four names appear twice and two appear once, giving 4 x 2 + 2 x 1 = 10 points. The eight labelled triangles turn out to be exactly the eight faces ABC, ACD, ADE, AEB, FBC, FCD, FDE, FEB, each used once, so no face is repeated or missing. Every name collects exactly 4 triangles, 240 degrees, which is what a vertex of a regular octahedron needs; and the labelled edges come out as 12 different pairs, each shared by exactly 2 faces, matching the octahedron's 12 edges. Finally, no triangle contains an opposite pair (A with F, B with D, C with E), as it must not. Folding a paper copy and reading the names off the finished solid confirms it.
Takeaway

Every edge of a solid has exactly two faces, so once one triangle of the net is named you can walk along the net naming one new point at a time — no guessing, and the 240 degrees at each corner proves you got it right.

  • List the 8 faces of the octahedron
  • Start from the triangle that is already named
  • Fold once: the first strip triangle, so L1 = F
  • Keep walking: L2 = D, then U3 = A
  • Finish the strip: L3 = E, U4 = B, L4 = F
  • The last triangle: BOT = D
  • Check every name collects a full 240 degrees
  • Check that opposite vertices never touch