Reasoning · Grade 6-1 Regular Polyhedra

Problem

Defining regular polyhedra and why only five

Five claims: only five kinds exist; all faces are congruent regular polygons; the same number of faces meets at each vertex; the angles at one vertex total under 360 degrees; the faces are only triangles, squares and regular hexagons. Exactly one claim is wrong. Pick it.
Regular tetrahedron Cube Regular octahedron Regular dodecahedron Regular icosahedron
Your answer
How to solve
Strategy Make a Systematic List — The statements that matter (1 and 5) both claim something about a complete list, so seeing five solids in a picture proves nothing — a picture cannot show that a sixth one is missing. Instead I build the list myself. A corner of a regular polyhedron is described by just two numbers: the shape of the face (how many sides it has) and how many faces meet there. So I make a systematic list running through face shapes — triangle, square, pentagon, hexagon, and beyond — and for each one test every possible number of faces per vertex against the 'less than 360 degrees' rule. That is a short list, because the angles grow and the test starts failing quickly. Whatever survives is the whole family; then I read all five statements off the finished list.
1STEP 1

What has to happen at one corner

A corner needs at least three faces totalling under 360.

3 ≤ (faces at a vertex) and (faces at a vertex) × (one face angle) < 360°
2STEP 2

The angle of each regular polygon

The regular angles run 60, 90, 108, 120, …

triangle 60°, square 90°, pentagon 108°, hexagon 120°, heptagon 128 4/7°, …
3STEP 3

Face = equilateral triangle (60 degrees): three counts work

Triangles allow 3, 4 or 5 at a corner.

3 × 60 = 180 ✓ 4 × 60 = 240 ✓ 5 × 60 = 300 ✓ 6 × 60 = 360 (lies flat)
4STEP 4

Face = square (90 degrees): one count works

Squares allow only 3.

3 × 90 = 270 ✓ 4 × 90 = 360 (lies flat)
5STEP 5

Face = regular pentagon (108 degrees): one count works

Pentagons allow only 3.

3 × 108 = 324 ✓ 4 × 108 = 432 (overlaps)
6STEP 6

Face = regular hexagon or anything bigger: nothing works

From hexagons on, nothing works.

3 × 120 = 360 (lies flat) 3 × 128 4/7 = 385 5/7 > 360 (overlaps)
7STEP 7

Collect the survivors — exactly five

So there are exactly five regular polyhedra.

3_triangle + 1_square + 1_pentagon = 5
8STEP 8

Judge the five statements against the finished list

The statement naming hexagons, number 5, is wrong.

Answer
5
3 + 1 + 1 = 5
The five corner types found (3, 4, 5 triangles; 3 squares; 3 pentagons) match the five named solids in the picture one for one, with none left over and none missing, and the face shapes seen in the picture are triangles, a square and a pentagon — exactly the three shapes the argument allows. The three rejected cases are all things you can see on a flat surface: 6 triangles, 4 squares and 3 hexagons around a point are the three ways to tile a floor with one regular shape, which is a good sign the cut-off at 360 degrees is in the right place. Each angle total is also a sensible size: they run 180, 240, 270, 300, 324 degrees, all under a full turn of 360, and the biggest gap (180 degrees, for the tetrahedron) belongs to the pointiest solid while the smallest gap (36 degrees, for the dodecahedron) belongs to the roundest, which is what the picture shows.
Takeaway

A corner needs a gap: add the angles meeting at a point, and if they reach 360 degrees the shape lies flat — that one rule leaves exactly five regular polyhedra, with triangle, square and pentagon faces, never hexagons.

  • What has to happen at one corner
  • The angle of each regular polygon
  • Face = equilateral triangle (60 degrees): three counts work
  • Face = square (90 degrees): one count works
  • Face = regular pentagon (108 degrees): one count works
  • Face = regular hexagon or anything bigger: nothing works
  • Collect the survivors — exactly five
  • Judge the five statements against the finished list