Reasoning · Grade 5-1 Rules and Correspondence

Problem

Regions of a circle cut by lines

Seven copies of the same circle each carry a target, from 5 parts up to 11 parts. Exactly 4 straight lines are drawn across each circle. The first, the 5-part circle, is already done with 4 parallel lines. Draw the lines so each circle splits into its target number of parts.
5 parts 6 parts 7 parts 8 parts 9 parts 10 parts 11 parts
Your answer
How to solve
Strategy Draw a Diagram — Six circles to fill in is a lot of trial and error if I just scribble lines and count. So I first do an easier related problem: put the lines in one at a time, starting from an empty circle, and watch what each new line does to the count. That gives a pattern, a rule connecting the number of parts to the number of crossing points inside the circle. Once I have the rule I do not need to hunt at all: for each target number the rule tells me exactly how many crossings I need, and then I only have to draw lines that cross the right number of times. Listing the possible numbers of crossings, 0 up to 6, in order is what shows that all seven targets are reachable and that nothing outside 5 to 11 is.
1STEP 1

Put the lines in one at a time and watch the count

Add lines one at a time and watch the count.

1 → 2 → 3 (parallel) or 1 → 2 → 4 (crossing)
2STEP 2

Turn that into one rule for the whole picture

The count is 5 plus the crossings.

parts = 1 + 4 + (crossings inside) = 5 + (crossings inside)
3STEP 3

Find how many crossing points are possible

Four lines cross at most 6 times.

4 × 3 ÷ 2 = 6 pairs, 5 + 0 = 5, 5 + 6 = 11
4STEP 4

Read off how many crossings each target needs

So the reachable counts run 5 to 11.

6 - 5 = 1, 7 - 5 = 2, 8 - 5 = 3, 9 - 5 = 4, 10 - 5 = 5, 11 - 5 = 6
5STEP 5

Draw the small counts: 5, 6, 7 and 8 parts

Small counts use plenty of parallel lines.

5 + 0 = 5, 5 + 1 = 6, 5 + 2 = 7, 5 + 3 = 8
6STEP 6

Draw the large counts: 9, 10 and 11 parts

Large counts tilt the lines apart to add crossings.

2 × 2 = 4 → 9, 4 + 1 = 5 → 10, 3 + 3 = 6 → 11
7STEP 7

Count the parts in every drawing to be sure

Counting each drawing matches its target.

3 + 8 = 11
Answer
make 0 up to 6 crossings
5 + crossings
The counts behave sensibly. With no crossings the 4 lines can only make strips, and 4 cuts across a circle always give 5 strips, so 5 really is the floor; adding a crossing can only ever increase the number of pieces, never decrease it. At the other end, 4 lines have only 6 pairs, so at most 6 crossings and at most 11 parts, and there is no way to reach 12. Every whole number from 5 to 11 is hit exactly once as the crossings run 0, 1, 2, 3, 4, 5, 6, so no target is missing and none is repeated. The 9-part grid can be checked at a glance, because its pieces really do sit in 3 rows of 3.
Takeaway

Every time two lines cross inside the circle you get one more piece, so count the crossings, add 5, and you know the answer before you shade anything in!

  • Put the lines in one at a time and watch the count
  • Turn that into one rule for the whole picture
  • Find how many crossing points are possible
  • Read off how many crossings each target needs
  • Draw the small counts: 5, 6, 7 and 8 parts
  • Draw the large counts: 9, 10 and 11 parts
  • Count the parts in every drawing to be sure