Problem
Reasoning · Grade 5-1 Number Puzzles
Find how big the right-hand side can be
The right side can never pass 9.
Reading the parentheses first is the whole skill here: the sum is computed before the division, so the largest sum over the smallest divisor gives the ceiling. Knowing the ceiling turns an open-ended puzzle into a short list.
5.OA.A.1Eliminate PossibilitiesBounding how large the right-hand side can be cuts the search down to a few products worth testing.
Why?
Bigger cards give bigger products, so once a product overshoots the bound every larger pairing overshoots too.
Why?
Every pairing outside the bound is thrown out without arithmetic, so only a short list has to be tested by hand.
List every product of two cards that is 9 or less
Products at most 9 are 2, 3, 4, 5, 6, 8.
Listing products in order is just the times table you already know, and ordering them makes it obvious where to stop - once the products pass 9 they can never come back.
3.OA.C.7Make A Systematic ListTest each case with the three cards that are left over
Testing the leftovers leaves three that work.
Checking 'does this divide exactly' is the multiple-and-factor idea from Grade 4 - you only need to ask whether the sum is in the divisor's times table, which is a one-second check for numbers this small.
4.OA.B.4Guess And CheckNotice the pattern in the three winners
All three share 3 + 5 on the right.
Re-sorting the three answers by what they have in common shows the puzzle has one hidden hinge - the sum 8 - and that spotting the hinge would have produced all three at once.
5.OA.A.2Organize Information In More WaysConfirm all five cards are used each time
Using all five cards gives the three with values 2, 4, 8.
The final check costs ten seconds and catches the most common slip in card puzzles, which is quietly reusing a card.
5.OA.A.1Make A Systematic ListAsk how big each side can possibly get first - once you know the answer is at most 9, only six products survive and you can check them all.
- Find how big the right-hand side can be
- List every product of two cards that is 9 or less
- Test each case with the three cards that are left over
- Notice the pattern in the three winners
- Confirm all five cards are used each time