Reasoning · Grade 5-1 Primes and Divisors

Problem

Prime factorization two ways

72 is broken down to primes in two different ways. A factor tree on the left, a stack of short divisions on the right. Both finish at the same prime factorisation. Do the same for 54 in both ways.
Method 1 72 8 9 4 2 3 3 2 2 72 = 2 × 2 × 2 × 3 × 3 Method 2 2 72 2 36 2 18 3 9 3
Your answer
How to solve
Strategy Look for a Pattern — The 72 example is a fully worked easier version of exactly the task I have, so I read the rule off it first: keep splitting until nothing splits any more. The factor tree is a drawing, so tool 1 does the work there; the short-division stack is the same information organised as a column instead of a tree, which is tool 15 — and comparing the two organisations is what makes the punchline visible. The punchline is a pattern: whichever split you start with, and whichever method you use, the collection of primes at the end is the same one.
1STEP 1

Read the stopping rule off the 72 example

The tree splits until every end is prime.

72 = 8 × 9 = (4 × 2) × (3 × 3) = (2 × 2 × 2) × (3 × 3)
2STEP 2

Method 1 — build a factor tree for 54

Splitting 54 as 6 and 9 ends at 2, 3, 3, 3.

54 = 6 × 9 = (2 × 3) × (3 × 3) = 2 × 3 × 3 × 3
3STEP 3

Start the tree differently and watch the ends stay the same

Splitting as 2 and 27 gives the same ends.

54 = 2 × 27 = 2 × 3 × 9 = 2 × 3 × 3 × 3
4STEP 4

Method 2 — divide 54 by small primes, over and over

The division stack divides by 2, 3, 3 in turn.

54 ÷ 2 = 27, 27 ÷ 3 = 9, 9 ÷ 3 = 3
5STEP 5

Read the answer off the stack and compare the two methods

The divisors and last quotient give 2 × 3 × 3 × 3.

54 = 2 × 3 × 3 × 3
6STEP 6

Write it in canonical form and check by multiplying back

Multiplying back gives 54.

54 = 2 × 3 × 3 × 3 = 2 × 3³, 2 × 27 = 54
Answer
2 × 3 × 3 × 3
2 × 27 = 54
Multiplying the answer back gives 2 × 3 × 3 × 3 = 54, so the size is right. Every factor listed really is prime — 2 and 3 have no divisors other than 1 and themselves — so the factorization is complete and none of the ends could split further. The digit-test check also agrees: 54 is even, so a 2 must appear, and its digit sum is 5 + 4 = 9, a multiple of 9, so at least two 3s are forced by that test. There is no digit-sum test for 27, so the exact count is settled by dividing instead: the third 3 and the 2 come from 54 ÷ 9 = 6 = 2 × 3. Comparing with the worked example is a further sanity check: 72 = 2³ × 3² and 54 = 2 × 3³ are both built only from 2s and 3s, which fits since 72 = 8 × 9 and 54 = 2 × 27 are both products of a power of 2 and a power of 3.
Takeaway

You can split a number any way you like, but you always end up with the same bag of primes — 54 is always one 2 and three 3s.

  • Read the stopping rule off the 72 example
  • Method 1 — build a factor tree for 54
  • Start the tree differently and watch the ends stay the same
  • Method 2 — divide 54 by small primes, over and over
  • Read the answer off the stack and compare the two methods
  • Write it in canonical form and check by multiplying back