Reasoning · Grade 5-1 Egyptian Fractions

Problem

Several ways to build unit-fraction sums

A unit fraction has 1 on top. Grab the biggest unit fraction that still fits underneath, and subtract it. If what is left is not a unit fraction, repeat. Write 4/9 and 23/36 as sums of unit fractions.
Your answer
How to solve
Strategy Solve an Easier Related Problem — The method is built to make the problem shrink: after each subtraction I am left with a smaller fraction and face exactly the same question again, so the whole task is one easy step repeated until the leftover is a unit fraction. Inside each step the only real decision is which unit fraction to take, and that is a bounded guess-and-check: try 1/2, then 1/3, then 1/4, … and stop at the first one that is smaller than the fraction in hand. I use the worked 3/7 example as the pattern to copy, and I check both finished answers by adding the unit fractions back up.
1STEP 1

How to find the largest unit fraction that fits

A unit fraction shrinks as its bottom grows.

1/2 > 1/3 > 1/4 > 1/5 > …
2STEP 2

(1) 4/9: the biggest unit fraction underneath it

The biggest fitting under 4/9 is 1/3.

1/3=3/9 < 4/9 < 9/18=1/2 → use 1/3
3STEP 3

(1) Subtract, and see that the job is already done

Subtracting leaves 1/9, already a unit fraction.

4/9-1/3=4/9-3/9=1/9
4STEP 4

(1) Write the answer and add it back up

So 4/9 = 1/3 + 1/9.

4/9=1/3+1/9
5STEP 5

(2) 23/36: the biggest unit fraction underneath it

The biggest fitting under 23/36 is 1/2.

1/2=18/36 < 23/36 < 36/36=1 → use 1/2
6STEP 6

(2) First subtraction

Subtracting leaves 5/36.

23/36-1/2=23/36-18/36=5/36
7STEP 7

(2) The biggest unit fraction underneath 5/36

The biggest fitting under 5/36 is 1/8.

1/8 < 5/36 < 1/7 → use 1/8
8STEP 8

(2) Second subtraction ends the process

Subtracting again leaves 1/72 and stops.

5/36-1/8=10/72-9/72=1/72
9STEP 9

Collect and verify both decompositions

Adding back confirms both answers.

1/2+1/8+1/72=36/72+9/72+1/72=46/72=23/36
Answer
1/3 + 1/9, 1/2 + 1/8 + 1/72
23/36 − 1/2 = 5/36
Both answers add back to exactly the fraction they came from — 3/9+1/9=4/9 and 36/72+9/72+1/72=46/72=23/36 — and every piece really is a unit fraction with all pieces different. The sizes are believable: 4/9 is a bit under a half, so its biggest piece should be 1/3 with a small tail, and it is; 23/36 is a bit under 2/3, so its biggest piece should be 1/2 with roughly 1/7 left over, and 1/8+1/72 is just that. The number of rounds also matches the method's own logic: the numerator falls from 23 to 5 to 1 in part (2) and from 4 to 1 in part (1), and the process must end once it reaches 1. Running the same greedy steps on the book's example reproduces 3/7=1/3+1/11+1/231 exactly, which confirms the procedure was applied the way the book intends.
Takeaway

Keep grabbing the biggest unit fraction that still fits and subtracting it — the leftover shrinks every time, so the process always finishes.

  • How to find the largest unit fraction that fits
  • (1) 4/9: the biggest unit fraction underneath it
  • (1) Subtract, and see that the job is already done
  • (1) Write the answer and add it back up
  • (2) 23/36: the biggest unit fraction underneath it
  • (2) First subtraction
  • (2) The biggest unit fraction underneath 5/36
  • (2) Second subtraction ends the process
  • Collect and verify both decompositions