Reasoning · Grade 4-2 Transformations and Angles

Problem

Angle where a rotated figure meets the original

Triangle ABC is turned 30 degrees clockwise about the point A. The turned copy is drawn on top of the original. Angle ACB is 60 degrees and angle AB′C′ is 70 degrees. Find the marked angle where side B′C′ crosses side AB.
60° 70° 1 A B C B' C'
Your answer
How to solve
Strategy Draw a Diagram — The crossing point has no name in the figure, so the very first thing to do is give it one - call it P - and mark it clearly on the diagram. Once P is on the page, a small triangle jumps out: A, B' and P. Two of its angles are things the turn hands me for free (30 degrees at A because that is how far everything turned, and 70 degrees at B' because it is printed), so the third angle comes from the triangle sum, and angle 1 is what is left of the straight line at P. Picturing the turn is what makes it obvious that the angle at A inside that little triangle really is the 30 degrees of the rotation.
1STEP 1

Write down what the turn gives you

A turn leaves every angle unchanged.

∠ AB'C' = ∠ ABC = 70°, ∠ AC'B' = ∠ ACB = 60°, ∠ BAB' = 30°
2STEP 2

Fill in the third angle of the triangle

The triangle's third angle is 50 degrees.

∠ BAC = 180° - 70° - 60° = 50°
3STEP 3

Name the crossing point and find the little triangle

Give the crossing point a name.

∠ B'AP = 30°, ∠ AB'P = 70°
4STEP 4

Get the third angle of triangle AB'P

In the small triangle that angle is 80 degrees.

∠ APB' = 180° - 30° - 70° = 80°
5STEP 5

Turn that into angle 1 using the straight line

Using the straight line gives 100 degrees.

① = 180° - ∠ APB' = 180° - 80° = 100°
6STEP 6

Cross-check by going the other way round

Chasing the other way also gives 100 degrees.

∠ BAC' = 50° - 30° = 20°, ① = 180° - 20° - 60° = 100°
Answer
100 degrees
180 − 80 = 100
The answer is an angle in degrees, and 100 degrees is a little more than a right angle - which matches the picture, where the marked angle at the crossing clearly opens wider than a square corner but is nowhere near a straight line. It also passes an internal test: the two angles at the crossing on the same side of line AB must add to 180 degrees, and 80 + 100 = 180. And the second route through triangle APC' gave 100 degrees using the 60 degrees at C', which the first route never touched, so both printed measurements have now been used and both agree. As a final sanity check, all the angles in the picture stay positive and sensible: 50 degrees at A, 70 at B, 60 at C, adding to 180, and the 20 degrees between AB and AC' is smaller than the 50 degrees between AB' and AC', as it must be.
Takeaway

Name the point the picture forgot to name, and the messy overlap turns into one small triangle whose angles you already know.

  • Write down what the turn gives you
  • Fill in the third angle of the triangle
  • Name the crossing point and find the little triangle
  • Get the third angle of triangle AB'P
  • Turn that into angle 1 using the straight line
  • Cross-check by going the other way round