Reasoning · Grade 3-2 Applications of Division

Problem

Trees along a road (fencepost)

Two plantings. (1) A 174 m straight road is planted both sides at 6 m spacing, ends included. (2) A pond of 180 m round is planted at 6 m spacing, with two maple trees in every gap. Tree thickness is ignored. Find each total.
Your answer
How to solve
Strategy Draw a Diagram — This is the classic fencepost idea, so I draw the layout and count gaps versus posts. On a straight road the posts are one more than the gaps (both ends counted); on a closed loop posts equal gaps. A tiny sketch (e.g. a 12 ft road) makes the +1 rule obvious before scaling up.
1STEP 1

P1: count the gaps on one side

174 ÷ 6 gives 29 gaps per side.

174 ÷ 6 = 29 gaps
2STEP 2

P1: trees on one side, then both sides

Ends included makes 30 a side, so 60 trees.

(29 + 1) × 2 = 30 × 2 = 60 trees
3STEP 3

P2: count the oaks around the loop

The loop closes, so the oaks match the gaps at 30.

180 ÷ 6 = 30 oaks (and 30 gaps)
4STEP 4

P2: add the maples and total

Two maples per gap makes 30 + 60 = 90.

30 × 2 = 60 maples; 30 + 60 = 90 trees
Answer
60 trees, 90 trees
P1: 30 trees per side at 6 ft spacing span 29 x 6 = 174 ft end to end, matching the road, and two sides give 60. P2: 30 oaks at 6 ft span 30 x 6 = 180 ft around the loop, matching the perimeter; with 60 maples the total 90 is sensible. The loop has no +1 while the open road does, which is the expected difference.
Takeaway

Count the gaps first: on a straight road add 1 for the end post, but on a loop the trees just equal the gaps -- the circle quietly saves you that extra tree!

  • P1: count the gaps on one side
  • P1: trees on one side, then both sides
  • P2: count the oaks around the loop
  • P2: add the maples and total