Reasoning · Grade 3-2 Finding Sums Using Products

Problem

Sum of consecutive numbers by pairing

Add every number from 1 to 100 the way Gauss did. Pair the smallest with the largest and work inward. There are 100 numbers, an even count, so nothing is left over. Find the total with a multiplication.
Your answer
How to solve
Strategy Look for a Pattern — Pairing the ends reveals that every pair adds to the same total, turning a long sum into one easy multiplication. I split the work into 'find the pair total' and 'count the pairs'.
1STEP 1

Pair the ends to find one fixed total

1 + 100, 2 + 99 — every pair makes 101.

1 + 100 = 2 + 99 = 3 + 98 = 101
2STEP 2

Count how many pairs there are

With 100 numbers there are 50 pairs.

100 ÷ 2 = 50
3STEP 3

Multiply pair total by number of pairs

Multiplying gives 50 × 101 = 5050.

50 × 101 = 5050
Answer
5050
50 × 101 = 5050
There are 100 numbers averaging about 50 (halfway between 1 and 100, namely 50.5), so the sum should be near 100 × 50.5 = 5050 — exactly what we got. The size (about five thousand) is sensible for adding numbers up to 100.
Takeaway

Pairing the smallest and largest numbers makes every pair the same, so a giant sum becomes one quick multiplication — Grade 3 thinking like Gauss!

  • Pair the ends to find one fixed total
  • Count how many pairs there are
  • Multiply pair total by number of pairs