Problem
Reasoning · Grade 3-2 Multiplication Patterns
(1) two-digit × two-digit = 4346
4346 ends in 6 from 3 × 2, giving 53 × 82.
A Grade 3 learner can test one promising pairing and multiply to confirm, using the ones-digit clue to avoid wild guessing.
3.NBT.A.2Guess And Check(2) three-digit × one-digit = 4256
4256 ÷ 8 is 532, so 532 × 8.
Checking the units: 8 times a number ending in 2 ends in 6, matching 4256, which points straight to 8 as the single factor.
3.NBT.A.3Analyze The UnitsBecause 8 times a number ending in 2 ends in 6, the single-digit factor of 4256 has to be 8.
Why?
The ones digit of a product depends only on the ones digits being multiplied, because every higher place carries a whole ten upward.
Why?
Testing each single-digit card against that ones-digit rule throws out every card but one, so no further searching is needed.
(3) two-digit × two-digit = 950
950 ends in 0, needing a 5 against an even: 25 × 38.
A product ending in 0 needs a 5 and an even number multiplied, so the units digit immediately tells me how to place the 5.
3.NBT.A.2Analyze The Units(4) three-digit × one-digit = 716
716 ÷ 2 is 358, so 358 × 2.
Because 716 is just over 700, the single factor must be the small card 2, and dividing back gives the three-digit number directly.
3.NBT.A.3Guess And CheckPeek at the last digit of the answer first — it tells you exactly where the 5 or the even card has to go, so you barely have to guess!
- (1) two-digit × two-digit = 4346
- (2) three-digit × one-digit = 4256
- (3) two-digit × two-digit = 950
- (4) three-digit × one-digit = 716