Reasoning · Grade 3-1 Multiplication and Division

Problem

Complete an arithmetic placement puzzle

Around a square border, eight number cells alternate with operation cells so each side reads as an equation. The digits 1 to 8 each appear once. All four equations must hold and the division must come out whole. Complete it in two different ways.
Your answer
How to solve
Strategy Make a Systematic List — The shared corner BR ties the addition and multiplication sides together, and the shared corner BL ties the division and multiplication sides. I anchor on the small, tightly constrained pieces (the multiplication BL x BM = BR and the division TL / LM = BL) to generate candidate corner values, then check the remaining numbers against the addition and subtraction sides, eliminating any filling that reuses a number.
1STEP 1

Map the four side equations

The four sides are minus, plus, times, divide and share their corners.

TL - TM = TR, TR + RM = BR, BL × BM = BR, TL ÷ LM = BL
2STEP 2

Use the multiplication side to find BR and BL

The product must stay under 9, so it is 2 × 4 or 2 × 3.

2 × 4 = 8 or 2 × 3 = 6
3STEP 3

Use the division side to fix TL and LM

The quotient is 2 as well, giving 6 ÷ 3 or 8 ÷ 4.

6 ÷ 3 = 2 or 8 ÷ 4 = 2
4STEP 4

Finish each case with the subtraction and addition sides

Fitting 1, 5, 7 into the minus and plus sides yields two layouts.

6-5=1, 1+7=8 and 8-7=1, 1+5=6
5STEP 5

Confirm exactly two fillings exist

Nothing else fits, so there are exactly two.

6-5=1, 1+7=8, 2×4=8, 6÷3=2
Answer
6−5=1, 1+7=8, 2×4=8, 6÷3=2 / 8−7=1, 1+5=6, 2×3=6, 8÷4=2
For both methods each of 1-8 appears exactly once, and all four equations check out: Method 1 gives 6-5=1, 1+7=8, 2x4=8, 6/3=2; Method 2 gives 8-7=1, 1+5=6, 2x3=6, 8/4=2. Both divisions come out whole, so both fillings are valid and they are genuinely different.
Takeaway

Start with the trickiest sides (the times and divide corners), lock those numbers in, and the add and subtract sides fall into place - all with Grade 3 number facts!

  • Map the four side equations
  • Use the multiplication side to find BR and BL
  • Use the division side to fix TL and LM
  • Finish each case with the subtraction and addition sides
  • Confirm exactly two fillings exist