Reasoning · Grade 3-1 Completing Equations

Problem

Build an equation meeting given conditions

A staircase sum: one-digit + two-digit + three-digit = four-digit. Each digit 0 to 9 is used exactly once overall. No number may lead with 0. Find the largest and the smallest possible sum.
Your answer
How to solve
Strategy Make a Systematic List — Think about place value: each digit contributes by where it sits. To make the sum large we want big digits in high-value addend places; to make it small we want small digits there. Then list candidate fillings near those targets and check the addition is correct and uses each digit once.
1STEP 1

See how each place pulls on the sum

The hundreds slot weighs most and the ones slots least.

addend total = 100h + 10(t₁ + t₂) + (o₁ + o₂ + o₃)
2STEP 2

Aim high for the largest sum

Big digits high gives the maximum 3 + 75 + 984 = 1062.

3 + 75 + 984 = 1062
3STEP 3

Confirm the largest sum uses every digit once

Counting the digits used: 0 to 9, once each.

984 + 75 + 3 = 1062
4STEP 4

Aim low for the smallest sum

The total must reach four digits, so the minimum is 3 + 45 + 978 = 1026.

3 + 45 + 978 = 1026
5STEP 5

Confirm the smallest sum uses every digit once

Its digits do not repeat either, so both stand.

978 + 45 + 3 = 1026
Answer
largest 1062, smallest 1026
Both sums are 4-digit numbers just above 1000, which makes sense because the most three addends like these can reach is around 1065 and they must total at least 1000. Both example fillings add up correctly and use each of 0-9 exactly once.
Takeaway

Knowing that hundreds count for more than ones lets you steer an addition to its biggest or smallest answer - that's just Grade 2 place-value sense!

  • See how each place pulls on the sum
  • Aim high for the largest sum
  • Confirm the largest sum uses every digit once
  • Aim low for the smallest sum
  • Confirm the smallest sum uses every digit once