Reasoning · Grade 3-1 Multiplication

Problem

Complete the multiplication equation

A two-digit times a one-digit must land on 7□6. The product lies from 706 to 796 and ends in 6. The two-digit factor is 10 to 99, the one-digit 1 to 9. Complete three different equations.
Your answer
How to solve
Strategy Make a Systematic List — The product must lie in the small range 706-796 and end in 6, so the candidate two-digit x one-digit pairs form a tiny finite set. Listing the multiples of each one-digit number that land in 706-796 and keeping those ending in 6 finds every valid equation.
1STEP 1

Bound the product

7□6 puts the product between 706 and 796, ending in 6.

706 ≤ product ≤ 796
2STEP 2

Search products ending in 6

Only a one-digit factor of 8 or 9 reaches that range, giving 84 × 9, 92 × 8, 97 × 8.

84 × 9 = 756, 92 × 8 = 736, 97 × 8 = 776
3STEP 3

Read off the tens digit

Reading the tens digit off each gives 5, 3, 7.

7 5 6, 7 3 6, 7 7 6
Answer
84 × 9 = 756, 92 × 8 = 736, 97 × 8 = 776
Each product is between 706 and 796, starts with 7, and ends with 6, matching 7□6. A systematic sweep of multipliers 1-9 turns up no other two-digit factor whose product fits, so exactly three completions exist.
Takeaway

Knowing just the first and last digit of the answer lets you hunt down every equation with Grade 3 times tables!

  • Bound the product
  • Search products ending in 6
  • Read off the tens digit