Patterns & Reasoning

Problem

Find the constant skip-count step

Four evenly spaced ticks 3829·3929·4029·4129 were made by skip-counting by the same step. How big is one step (●)?
3829 3929 4029 4129
Base-ten numbers
Your answer
How to solve
1STEP 1

Subtract two neighbors

The gap between two neighbors is one step. 3929 minus 3829 is 100.

3929 − 3829 = 100
2STEP 2

Confirm the step repeats

Every other gap is 100 too — so the skip step is 100.

4029 − 3929 = 100 · 4129 − 4029 = 100
Answer
100
3929 − 3829 = 100
Check — counting on by 100 from 3829 gives 3929, 4029, 4129, exactly the labels shown. Even the first-to-last span 300 split over three jumps is 300 ÷ 3 = 100.
Takeaway

For evenly skip-counted numbers, subtract two neighbors to find one step — it's the gap of one tick, not the whole span.

  • Subtract two neighbors (3929 − 3829)
  • Check every gap matches
  • One step = 100
Where next?
Another one like thissuggested
Step back and solidifysuggested

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