Problem
Find the sticks for the squares
5 squares, each needing 4 sticks — that's 5 × 4 = 20 sticks.
The 5 squares split the sticks into five separate groups, each holding the 4 sticks of one square — one stick per side, four sides, so exactly 4 sticks each. With five such equal groups, they're counted in one multiplication, 5 × 4.
Identify Subproblems3.OA.A.1Multiplication FactsBuilding the 5 squares uses 5 × 4 = 20 sticks in all.
Why?
The five squares split the sticks into five separate groups, each group holding the 4 sticks of one square.
Why?
One square needs exactly 4 sticks, one stick for each of its four sides.
Why?
Each side is matched with its own single stick, so four sides take four sticks.
Why?
No sticks are shared between shapes, so the five groups never overlap and can be counted separately and added.
Why?
Five equal groups of 4 sticks are totaled by the multiplication 5 × 4.
Find the sticks for the triangles
4 triangles, each needing 3 sticks — that's 4 × 3 = 12 sticks.
The 4 triangles split the sticks into four separate groups, each holding the 3 sticks of one triangle — one stick per side, three sides, so exactly 3 sticks each. With four such equal groups, they're counted in one multiplication, 4 × 3.
Identify Subproblems3.OA.A.1Add the two totals
No sticks are shared, so 20 and 12 add up to 32 sticks in all.
Squares and triangles never share sticks, so the two groups don't overlap. Since the whole equals the sum of its non-overlapping parts, adding the 20 sticks for squares and the 12 for triangles gives the total directly.
Identify Subproblems3.OA.A.3Count each shape with equal-groups multiplication, then add the totals — 5 × 4 for squares, 4 × 3 for triangles.
- Find the squares' sticks (5 × 4 = 20)
- Find the triangles' sticks (4 × 3 = 12)
- Add for the total → 32