Patterns & Reasoning

Problem

Locate and compare numbers on a number line

Of the three numbers 8,800, 10,500, and 10,100, decide which one is nearest to 10,000.
Base-ten numbers
Your answer
How to solve
Strategy Draw a Diagram — Picture the numbers on a number line around 10,000 and measure how far each is from 10,000; the one with the smallest gap is closest.
1STEP 1

Distance of 8,800 from 10,000

8,800 is below 10,000 by 10,000 - 8,800 = 1,200.

10,000 - 8,800 = 1,200
2STEP 2

Distance of 10,500 from 10,000

10,500 is above 10,000 by 10,500 - 10,000 = 500.

10,500 - 10,000 = 500
3STEP 3

Distance of 10,100 from 10,000

10,100 is above 10,000 by 10,100 - 10,000 = 100.

10,100 - 10,000 = 100
4STEP 4

Compare the gaps

The distances are 1,200, 500, and 100. The smallest is 100, so 10,100 is closest to 10,000.

100 is less than 500, which is less than 1,200
Answer
10,100
10,100 differs from 10,000 by only 100, far less than 500 (for 10,500) or 1,200 (for 8,800), so 10,100 being closest is correct.
Takeaway

This only needs Grade 4 comparing: measure each number's gap from 10,000 and pick the smallest gap!

  • Distance of 8,800 from 10,000
  • Distance of 10,500 from 10,000
  • Distance of 10,100 from 10,000
  • Compare the gaps
Where next?
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▶ Practice — 10 problems