Numbers & Place Value

Problem

Compare place by place to bound an unknown digit

Find every single digit 0-9 that can replace the box so that 4,541,592 is greater than 45□6,719.
Base-ten numbers
Your answer
How to solve
Strategy Make a Systematic List — Both numbers have the same number of digits, so I line them up place by place from the left and compare; the first place where they differ decides which is larger, which bounds the box digit. I then list every digit that fits.
1STEP 1

Line up the digits

Both numbers are seven digits: 4 541 592 versus 4 5□ 6 719. Compare from the top and the leading digits agree: 4 = 4, then 5 = 5.

4 5 4 1 5 9 2 vs 4 5 □ 6 7 1 9
2STEP 2

Reach the deciding place

The first two leading digits match (4=4, 5=5). The next place is the ten-thousands place: the fixed number has 4 there, the other has the box. To keep 4,541,592 the bigger number, 4 must be at least as large as the box. If the box were also 4, we would have to look further; if it is smaller than 4, the fixed number already wins here.

4 ? □
3STEP 3

Test the tie case box = 4

If the box is 4, the other number is 4,546,719. Comparing 4,541,592 with 4,546,719 the next differing place gives 1 versus 6, so 4,541,592 is smaller. So box = 4 fails, and box must be strictly less than 4.

4,541,592 less than 4,546,719
4STEP 4

List the working digits

The box must be smaller than 4, so it can be 0, 1, 2, or 3. Each makes 45□6,719 at most 4,536,719, which is less than 4,541,592.

□ ∈ {0,1,2,3}
Answer
0, 1, 2, 3
With box = 3, 45□6,719 = 4,536,719 less than 4,541,592 (true). With box = 4, 4,546,719 greater than 4,541,592 (false). The cutoff at 4 is correct, so 0,1,2,3 are exactly the digits that work.
Takeaway

This only needs Grade 4 comparing: line the numbers up and the first place they differ tells you the answer!

  • Line up the digits
  • Reach the deciding place
  • Test the tie case box = 4
  • List the working digits
Where next?
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▶ Practice — 10 problems