Operations & Word Problems

Depth · one concept from first principles · step 2 of 4

Count the children two ways and equate

With 18 children per room, the kindergarten needs exactly one more room than it has. Mixing 18-child and 19-child classes in the ratio 4:3 fills every room exactly. Find the number of children.
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Your answer
How to solve
Strategy Convert to Algebra — Let the class counts be 4x and 3x, so there are 7x rooms. Count the children once from the first plan and once from the second plan, and set the two counts equal.
1STEP 1

Name the class counts

The ratio 4:3 means 4x classes of 18 and 3x classes of 19, so 7x classrooms in all.

4x + 3x = 7x
2STEP 2

Count children from the first plan

With 18 per class, one extra room's worth of children is left over, so there are enough children for 7x + 1 classes of 18.

18(7x + 1)
3STEP 3

Count children from the second plan

Add up the 18-child and the 19-child classes.

18 × 4x + 19 × 3x = 72x + 57x = 129x
4STEP 4

Equate and solve

Both expressions count the same children.

126x + 18 = 129x → 3x = 18 → x = 6
5STEP 5

Find the number of children

There are 7 × 6 = 42 classrooms.

18 × (42 + 1) = 18 × 43 = 774
Answer
774 children
24 classes of 18 and 18 classes of 19 hold 432 + 342 = 774 children in 42 rooms, in the ratio 24 : 18 = 4 : 3. And 774 ÷ 18 = 43, one more than 42 rooms.
Takeaway

When two plans place the same children, count them both ways and set the counts equal.

  • Name the class counts
  • Count children from the first plan
  • Count children from the second plan
  • Equate and solve
  • Find the number of children
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