Numbers & Place Value

Problem

Place digit cards for largest or smallest product

Using three of the four cards 2, 4, 5, 6 (each used once), build a (two-digit number) times (one-digit number). I need the largest possible product and the smallest possible product.
Base-ten numbersOperations
Your answer
How to solve
Strategy Guess and Check — There are only a handful of sensible arrangements, so make a short systematic list of the strong candidates and check each product. For the largest product, big digits in high place values matter; for the smallest, small digits do. Testing the top few candidates each way pins down the extremes with certainty.
1STEP 1

Aim for the largest product

To make the product large, the multiplier should be large and the two-digit number large. Test 65 × 4, 64 × 5, and 54 × 6.

65 × 4 = 260, 64 × 5 = 320, 54 × 6 = 324
2STEP 2

Pick the maximum

Among the candidates, 54 times 6 gives the biggest product, so the largest possible product is 324.

54 × 6 = 324
3STEP 3

Aim for the smallest product

To make the product small, the multiplier should be small (the card 2) and the two-digit number small. Test 45 × 2 and 46 × 2.

45 × 2 = 90, 46 × 2 = 92
4STEP 4

Pick the minimum

The smallest of these is 45 times 2, so the smallest possible product is 90.

45 × 2 = 90
Answer
Largest product 324 (54 × 6); smallest product 90 (45 × 2)
Both products use exactly three of the four cards once. 324 is near the top of what these cards allow (under 70 times 6 = 420 but using only valid cards), and 90 is small as expected with the 2 as multiplier. A quick scan of other arrangements (65 times 4 = 260, 56 times 4 = 224) stays between 90 and 324, confirming the extremes.
Takeaway

Big digit as the multiplier for the most, small digits for the least: Grade 3 place-value thinking!

  • Aim for the largest product
  • Pick the maximum
  • Aim for the smallest product
  • Pick the minimum
Where next?
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▶ Practice — 10 problems