Problem
Start with the thousands place
To beat 5000 the thousands digit must be 5 or more — only 5 and 8 work. (0 can't lead)
The thousands place is worth 1000, but the three lower places together reach only 999, so the thousands digit alone decides whether you clear 5000.
Identify SubproblemsFour Digit Numbers4.NBT.A.2A four-digit number built from the cards 8, 0, 5, and 3 is greater than 5000 exactly when the card in the thousands place is 5 or 8.
Why?
Whether a four-digit number clears 5000 is settled by its thousands digit alone, because that place is worth a whole thousand.
Why?
Moving the thousands digit up by one adds a full 1000, while the hundreds, tens, and ones places together can only ever reach 999, so they can never make up for a smaller thousands digit.
Why?
Each place holds ten of the place beneath it, so one thousand is bigger than any amount the three lower places can pile up.
Why?
Of the four cards, only 5 and 8 are large enough in the thousands place to pass 5000, while 3 keeps the number down in the 3000s and 0 cannot lead a four-digit number at all.
Why?
Because the thousands digit decides the size, a 3 there gives a number below 4000, and a 0 there means there is no thousands at all, so the leading card has to be 5 or 8.
List the rest, none missed
The three remaining cards arrange 6 ways — both cases stay above 5000.
Three choices for the first slot, two for the next, one left for the last gives 3×2×1=6 orderings.
Make Systematic List4.NBT.A.2Add the two cases
The 5- and 8-lists don't overlap — just add them.
Because the leading digits 5 and 8 differ, no number lands in both lists, so the counts add without overlap.
Make Systematic List4.NBT.A.2Look at the biggest place first. Only cards 5 and 8 lead a number past 5000; for the rest, just list systematically and count.
- Split by the thousands digit (5 · 8)
- List the rest, none missed (6 + 6)
- Add up → 12