Numbers & Place Value

Problem

Recover missing digits from column carries

A two-digit number with tens digit A and ones digit B is multiplied by 6, and the product is 288. We must find the digits A and B.
Base-ten numbersOperations
Your answer
How to solve
Strategy Work Backwards — The result of the multiplication is given, so we undo it: dividing 288 by 6 recovers the two-digit number, and reading its digits gives A and B. A quick column check confirms the carry.
1STEP 1

Undo the multiplication

Since the two-digit number times 6 equals 288, divide 288 by 6 to recover the number.

288 ÷ 6 = 48
2STEP 2

Read off the digits

The recovered number is 48, so the tens digit A is 4 and the ones digit B is 8.

48 → A = 4, B = 8
3STEP 3

Check the column multiplication

Rebuild the product column by column to confirm 48 × 6 lands back on 288.

48 × 6 = 288
Answer
A = 4, B = 8
288 ÷ 6 = 48 → A = 4, B = 8
48 times 6 = 288 exactly, and both A=4 and B=8 are valid single digits with A not zero, so the two-digit number 48 is legitimate.
Takeaway

When you know the answer to a times problem, just divide to walk backwards to the hidden number, then read its digits!

  • Undo the multiplication
  • Read off the digits
  • Check the column multiplication
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▶ Practice — 10 problems