Different factor pairs, same product
A piece of wire is as long as a stick laid end to end times. Using this wire, what is the greatest number of triangles you can make if each triangle has three sides that are all long?
Show solution
Understand
A wire is as long as a 9 cm stick placed end to end 4 times. Each triangle is made of three 2 cm sides. We want the greatest number of such triangles the wire can make.
- The wire length equals a 9 cm stick laid end to end 4 times.
- Each triangle has three sides, each 2 cm long.
- The greatest number of 2 cm equilateral triangles the wire can make.
- Each triangle uses exactly 3 sides of 2 cm.
- Whole triangles only (you cannot use part of a triangle).
Plan
#7 Identify Subproblems · also uses: #8 Analyze the Units
Break the problem into two small steps: first find the total wire length, then find how much wire one triangle needs, and finally see how many triangles fit. Tracking centimeters keeps the multiplication and division lined up correctly.
Execute
Review
6 triangles use 6 times 6 = 36 cm, which is exactly the whole wire, so the answer fits with nothing wasted and the magnitude is sensible.
You could repeatedly subtract 6 cm from 36 cm (36, 30, 24, 18, 12, 6, 0) and count the 6 subtractions, which is the Guess-and-Check / repeated-subtraction view of the same division.
Standards · min grade 4
3.OA.B.5Apply properties of operations as strategies to multiply and divide — Multiplying 9 by 4 to get the total wire length and 2 by 3 for one triangle's wire.4.OA.B.4Find all factor pairs and recognize multiples; determine prime or composite — Recognizing that 36 splits into equal groups of 6, giving 6 triangles.