Data & Graphs

Problem

Estimate an unmeasured midpoint value on a line graph

A line graph of town temperature shows 8 a.m. = 6, 10 a.m. = 8, 12 noon = 11, 2 p.m. = 15, 4 p.m. = 12 degrees C (each square = 1 degree). 1:00 p.m. was not measured; I estimate it as the midpoint of the 12 noon and 2 p.m. readings.
Town Temperature 5 10 15 (°C) 8 10 12 2 4 a.m. p.m. Time
Measurement & data
Your answer
°C
How to solve
Strategy Look for a Pattern — On a line graph the segment between two points rises steadily, so the value halfway across is the average of the two endpoints. 1 p.m. is the halfway time between 12 noon and 2 p.m., so I take the midpoint of 11 and 15.
1STEP 1

Add the two endpoint temperatures

Add the two readings on either side of 1 p.m.: 11 + 15 = 26.

11 + 15 = 26
2STEP 2

Halve to get the midpoint

Divide the sum by 2 to find the midpoint value: 26 ÷ 2 = 13 degrees C.

26 ÷ 2 = 13
Answer
13 °C
(11 + 15) ÷ 2 = 13
13 lies between 11 (noon) and 15 (2 p.m.), as it must for a time in between, and it is exactly in the middle, which fits 1 p.m. being the middle time. The magnitude is sensible for an early-afternoon temperature.
Takeaway

Halfway across a line segment means halfway up - just average the two end values!

  • Add the two endpoint temperatures
  • Halve to get the midpoint
Where next?
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▶ Practice — 8 problems