Reasoning · Grade 6-2 Surface Area of Cube Stacks

Problem

Largest and smallest surface area

Twelve unit cubes are given. All twelve build a rectangular box with no gaps or overhang. Several different boxes are possible. Find the smallest possible surface area.
Your answer
How to solve
Strategy Make a Systematic List — The word 'smallest' means I have to be sure that nothing beats my answer, and the only honest way to be sure is to list every box that can be built and compare them all. Luckily there are very few: the three edge lengths are whole numbers whose product is 12, so writing the factor triples of 12 in order (smallest edge first) catches every possible box exactly once. Building the four boxes out of real cubes, or sketching them, makes the pattern obvious — the more the box looks like a cube, the tighter its skin. A second way of looking at it (changing focus from the outside faces to the hidden ones) explains why: the 12 cubes always contribute 72 faces in total, and every place where two cubes touch hides 2 of them, so the box with the most touching pairs has the least surface. That gives me an independent check on the list.
1STEP 1

Turn 'box made of 12 cubes' into 'three numbers that multiply to 12'

A box is three numbers multiplying to 12.

a × b × c = 12
2STEP 2

List every factor triple of 12, with no repeats and nothing missed

There are only four such triples.

12 = 1 × 1 × 12 = 1 × 2 × 6 = 1 × 3 × 4 = 2 × 2 × 3
3STEP 3

Work out the surface area of each box on the list

Their surfaces are 50, 40, 38, 32.

S = 2(ab + bc + ac); 1×1×12: 2(1+12+12) = 50; 1×2×6: 2(2+12+6) = 40; 1×3×4: 2(3+12+4) = 38; 2×2×3: 2(4+6+6) = 32
4STEP 4

Pick the smallest, and see why it is the boxiest box

The smallest is the boxiest one, 32.

50 > 40 > 38 > 32
5STEP 5

Check it a different way: count hidden faces instead of outside faces

Counting joints also gives 32.

S = 6 × 12 - 2 × (touching pairs); 2×2×3: 72 - 2 × 20 = 32; 1×1×12: 72 - 2 × 11 = 50
Answer
32 square inches
2 × 2 × 3 = 12
The units are right: an area answer in square inches, built from products of two edge lengths in inches. The magnitude is sensible too. The 12 loose cubes, if none of them touched, would show 12 times 6 = 72 square inches of face, so any stacked box must come in well under 72 — and 32 does. It must also be more than the surface of a solid cube of the same volume, and a 2 by 2 by 2 cube (only 8 cubes) already has surface 24, so 32 for a slightly bigger, slightly less cube-like solid is exactly the right neighbourhood. Finally, 32 is the smallest of the four values 50, 40, 38, 32, and the list of four is provably complete because it is the complete list of factor triples of 12.
Takeaway

Pack the cubes into the boxiest box you can — 2 by 2 by 3 — and the skin shrinks to 32 square inches, because squishing cubes together hides faces.

  • Turn 'box made of 12 cubes' into 'three numbers that multiply to 12'
  • List every factor triple of 12, with no repeats and nothing missed
  • Work out the surface area of each box on the list
  • Pick the smallest, and see why it is the boxiest box
  • Check it a different way: count hidden faces instead of outside faces