Reasoning · Grade 6-1 Distance and Speed (2)

Problem

Round trip at two different speeds

The same stretch is covered twice, out and back. The speed differs each way. Part (1) gives the length and both speeds; part (2) gives both speeds and the total time. Find the time in (1) and the length in (2).
Your answer
How to solve
Strategy Analyze the Units — Hours is the thing that adds up, so keep everything in hours: miles divided by miles-per-hour gives hours, and the two leg-hours can then be added. That single habit protects against the classic mistake of averaging the two speeds. For part (2) the trail length is unknown, so instead of naming it with a letter I shrink the problem (tool 9): ask how many hours ONE mile of trail costs — 1/3 of an hour going up plus 1/6 of an hour coming down — and then see how many of those one-mile round trips fit into 12 hours. A simple out-and-back arrow diagram keeps the two legs separate so neither is double-counted.
1STEP 1

(1) Draw the trip as two separate legs

Draw it as two legs.

2STEP 2

(1) Time the outbound leg

The outbound leg takes 4 hours.

20 ÷ 5 = 4 hours
3STEP 3

(1) Time the return leg

The return leg takes 2 hours.

20 ÷ 10 = 2 hours
4STEP 4

(1) Add the two leg times

Together that is 6 hours.

4 + 2 = 6 hours
5STEP 5

(2) Shrink it: how long does ONE mile of trail cost?

In (2) one unit of trail costs half an hour.

1/3 + 1/6 = 2/6 + 1/6 = 3/6 = 1/2 hour per mile of trail
6STEP 6

(2) See how many one-mile round trips fit in 12 hours

Twelve hours buys 24 miles.

12 ÷ 1/2 = 12 × 2 = 24 miles
7STEP 7

(2) Check the 24 miles against the story

Checking back gives 12 hours.

24 ÷ 3 = 8, 24 ÷ 6 = 4, 8 + 4 = 12 ✓
Answer
6 hours, 24 miles
4 + 2 = 6, 12 ÷ 1/2 = 24
The units land where they should: miles divided by miles-per-hour gives hours in (1), and hours divided by hours-per-mile gives miles in (2). Magnitudes are sensible too. In (1) the whole trip is 40 miles of travel and the speeds are between 5 and 10 miles per hour, so the total must lie between 40/10 = 4 hours and 40/5 = 8 hours; 6 hours sits comfortably inside that window, and it must be nearer the slow end than a plain average would suggest, which it is. In (2), 12 hours of walking at speeds of 3 and 6 miles per hour means somewhere between 12 x 3 = 36 and 12 x 6 = 72 miles of walking, i.e. a trail between 18 and 36 miles; 24 miles fits, and the 8-hours-up / 4-hours-down split reproduces the given 12 hours exactly.
Takeaway

On a round trip at two speeds, add the time for each leg — never average the speeds, because you spend longer going slow than coming back fast.

  • (1) Draw the trip as two separate legs
  • (1) Time the outbound leg
  • (1) Time the return leg
  • (1) Add the two leg times
  • (2) Shrink it: how long does ONE mile of trail cost?
  • (2) See how many one-mile round trips fit in 12 hours
  • (2) Check the 24 miles against the story