Reasoning · Grade 6-1 Dual and Semiregular Polyhedra

Problem

Semiregular solids by cutting off vertices

Three columns must be joined with lines. Left: regular polyhedra. Middle: ways of changing one. Right: the resulting semiregular solids. Each entry pairs with exactly one in each column. Join the three columns correctly.
Regular polyhedron Method Semiregular polyhedron Made by slicing a regular tetrahedron through the points that divide each of its edges into 3 equal parts. Made by slicing a regular octahedron through the points that divide each of its edges into 3 equal parts. Made by slicing a cube through the points that divide each of its edges into 2 equal parts. Made by pulling the faces of a regular dodecahedron apart by a suitable gap and filling in the spaces between them with equilateral triangles.
Your answer
How to solve
Strategy Visualize Spatial Relationships — Rather than trying to picture each finished solid whole, I shrink the question to a single corner: what does one cut do to one vertex, and what does it do to one face? Those two easier questions have short answers - a vertex where k faces meet becomes a k-sided face, and a face gets its corners trimmed - and together they tell me the two kinds of face the new solid has. Since the four pictures in the right column have four different pairs of face shapes (hexagon+triangle, square+triangle, hexagon+square, pentagon+triangle), naming the pair is enough to pick the picture, and after each match the remaining choices shrink.
1STEP 1

Do the easy half first: match the left column to the methods

The methods' names match the left column at once.

2STEP 2

Work out what a corner cut does to one vertex

Cutting a corner creates a new face there.

faces meeting at a vertex = k → new face is a k-gon
3STEP 3

Work out what the cut does to an original face

Cutting at third-points doubles the face's sides.

cut at thirds: n-gon → 2n-gon; cut at midpoints: n-gon → n-gon
4STEP 4

Apply both rules to the regular tetrahedron (M1)

The tetrahedron gives hexagons and triangles.

3 × 2 = 6 (hexagon faces), k = 3 (triangle faces)
5STEP 5

Apply both rules to the regular octahedron (M2)

The octahedron gives hexagons and squares.

3 × 2 = 6 (hexagon faces), k = 4 (square faces)
6STEP 6

Apply both rules to the cube (M3)

Cutting the cube at midpoints gives squares and triangles.

n = 4 (square faces stay squares), k = 3 (triangle faces)
7STEP 7

Read off the dodecahedron method (M4) and check the last picture

The remaining method is the dodecahedron's, matching the last picture.

8STEP 8

Check the pairing is one-to-one

The three columns pair up one to one.

Answer
tetrahedron, octahedron, cube, dodecahedron in turn
3 × 2 = 6
Every answer keeps the defining property of a semiregular solid: exactly two kinds of regular polygon, arranged the same way at every vertex. The face counts also come out as whole numbers that match the pictures - tetrahedron: 4 hexagons + 4 triangles = 8 faces; octahedron: 8 hexagons + 6 squares = 14 faces; cube: 6 squares + 8 triangles = 14 faces; dodecahedron: 12 pentagons + 80 triangles = 92 faces, which is why that one looks like a ball. A second check is that no method can invent faces out of nothing: each original face becomes exactly one new face and each vertex becomes exactly one new face, so faces-after = faces-before + vertices-before. For the tetrahedron 4 + 4 = 8, for the octahedron 8 + 6 = 14, for the cube 6 + 8 = 14 - all three agree with the counts above. Finally the odd one out behaves as it should: the midpoint cut is the only one that does not double the number of sides of a face, and it is the only answer picture with squares rather than octagons.
Takeaway

Slice a corner off and you get a new face with one side for every face that met there - so counting what meets at one corner tells you what the whole new solid is made of.

  • Do the easy half first: match the left column to the methods
  • Work out what a corner cut does to one vertex
  • Work out what the cut does to an original face
  • Apply both rules to the regular tetrahedron (M1)
  • Apply both rules to the regular octahedron (M2)
  • Apply both rules to the cube (M3)
  • Read off the dodecahedron method (M4) and check the last picture
  • Check the pairing is one-to-one