Reasoning · Grade 6-1 Dual and Semiregular Polyhedra

Problem

Dual polyhedron from face centers

Put one dot at the middle of every face of a solid. Join two dots whenever their faces share an edge. The dots and segments form a new solid inside. Say what comes out of a tetrahedron and a cube.
(1) Regular tetrahedron (2) Cube
Your answer
How to solve
Strategy Draw a Diagram — Trying to see the inner solid through the outer one is hard, so instead I find the rule that turns the old counts into the new counts, and then read the answer off the numbers. Each dot sits on a face, so faces turn into vertices. Each segment sits across an edge, so the edge count does not change at all. And each face of the new solid wraps round one old vertex, so vertices turn into faces. Written as one line: faces and vertices swap places, edges stay put. I start with the tetrahedron, which is the easier case because you can see every dot at once, and use it to check the rule; then I apply the rule to the cube, where the inner solid is hidden.
1STEP 1

Where do the new vertices come from?

Each new vertex comes from an old face.

(new vertices) = (old faces)
2STEP 2

Where do the new edges come from?

Each new edge pairs with an old edge.

(new edges) = (old edges)
3STEP 3

Where do the new faces come from?

Each new face comes from an old vertex.

(new faces) = (old vertices), (sides of a new face) = (faces at an old vertex)
4STEP 4

State the rule

So faces and vertices trade places.

f ⇔ v, e → e
5STEP 5

Part (1): the regular tetrahedron

A tetrahedron gives back a tetrahedron.

f = 4, e = 6, v = 4 ⟶ v' = 4, e' = 6, f' = 4
6STEP 6

Part (2): the cube

A cube gives an octahedron.

f = 6, e = 12, v = 8 ⟶ v' = 6, e' = 12, f' = 8
Answer
a tetrahedron, an octahedron
6 → 8, 8 → 6
Euler's formula holds for both new solids: the tetrahedron gives 4 + 4 - 6 = 2 and the octahedron gives 6 + 8 - 12 = 2, so the counts are those of a genuine polyhedron. The rule is also self-consistent — apply it twice and you should get back where you started, and you do: cube (6, 12, 8) becomes octahedron (8, 12, 6), and the octahedron becomes (6, 12, 8), the cube again. The tetrahedron is its own partner, which is exactly what you would expect from a solid whose face count and vertex count are already equal. Sizes are sensible too: the new solid always sits strictly inside the old one, since every dot is inside a face, and it never has more edges than the original, since edges are matched one to one.
Takeaway

Dots in the middles of the faces build a new solid where faces and corners trade places and the edges stay the same in number — so a cube turns into a regular octahedron, and a regular tetrahedron turns back into itself.

  • Where do the new vertices come from?
  • Where do the new edges come from?
  • Where do the new faces come from?
  • State the rule
  • Part (1): the regular tetrahedron
  • Part (2): the cube