Reasoning · Grade 5-2 Varieties of Magic Squares

Problem

Magic sums on the edges of a cube

Each of a cube's 12 edges carries a circle at its middle. Six are filled: 1, 12, 2 on the top face's back, left and right edges, 8 on the front-right upright, 4 and 5 on the bottom face's front and left edges. The numbers 1 to 12 are each used once. Fill the rest so every face's four circles total the same.
Your answer
How to solve
Strategy Change Focus / Count the Complement — The face total is not given, and no face can be filled until it is known. Rather than guess it, I add up all six faces at once: because each edge of a cube borders exactly two faces, that grand total counts each of the numbers 1 to 12 exactly twice, which fixes the face total in a single division. Once the total is known, the picture takes over — the top face has only one empty circle, and every circle I write turns another face into a one-blank face. Right at the end three circles remain on three faces at once, and the same double-counting trick cracks that too.
1STEP 1

See which four edges bound each face

Each face is bounded by four edges.

2STEP 2

Add all six faces at once to find the face total

Adding all six double-counts each number, giving 26.

1+2+3+…+12 = 78, 78 × 2 = 156 = □ × 6, □ = 156 ÷ 6 = 26
3STEP 3

The top face has only one empty circle

The top face's blank is 11.

26-(12+1+2) = 26-15 = 11
4STEP 4

Now the front face has only one empty circle

The front face's blank is 3.

26-(11+4+8) = 26-23 = 3
5STEP 5

And then the left face

The left face's blank is 6.

26-(12+3+5) = 26-20 = 6
6STEP 6

Three circles left, and each of the last three faces still has two blanks

The last three faces each have two blanks.

right: 26-(2+8) = 16, bottom: 26-(4+5) = 17, back: 26-(1+6) = 19
7STEP 7

Double-count again on just those three faces

Double-counting again gives 10, 9 and 7.

16+17+19 = 52 = 2 × 26; 26-16 = 10, 26-17 = 9, 26-19 = 7
8STEP 8

Check all six faces on the real cube

All six faces total 26.

1+12+2+11 = 11+3+8+4 = 12+3+6+5 = 2+8+9+7 = 1+6+9+10 = 4+5+7+10 = 26
Answer
26
78 × 2 ÷ 6 = 26
The face total of 26 is the right size: four numbers averaging 6.5, the middle of 1 to 12, give 4 x 6.5 = 26, so no other value could work for all six faces at once. All six face totals were re-added on the cube and every one is 26, and the twelve entries sort to exactly 1 through 12 with nothing repeated or missing. The three numbers found last, 7, 9 and 10, are precisely the three that were still unused, which could not have happened by accident. Every circle after the first was forced by a subtraction, so this is the only way to fill the cube.
Takeaway

Every edge of a cube belongs to two faces, so adding all six faces counts each number twice — that doubling is what tells you the face total is 26.

  • See which four edges bound each face
  • Add all six faces at once to find the face total
  • The top face has only one empty circle
  • Now the front face has only one empty circle
  • And then the left face
  • Three circles left, and each of the last three faces still has two blanks
  • Double-count again on just those three faces
  • Check all six faces on the real cube